我试图以一种格式输出以下数组。它没有得到
package com.idal.cib;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.SQLException;
public class DatabaseConnector {
static Connection conn1 = null;
public static Connection getDbConnection(String driver, String url,
String username, String password) {
// TODO Auto-generated constructor stub
try {
Class.forName(driver);
conn1 = DriverManager.getConnection(url, username, password);
} catch (ClassNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (SQLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return conn1;
}
}
package com.idal.cib;
import java.io.FileWriter;
import java.io.IOException;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.ResultSetMetaData;
import java.sql.SQLException;
import java.util.ArrayList;
import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
public class DBJsonConverter {
static ArrayList<String> data = new ArrayList<String>();
static Connection conn = null;
static PreparedStatement ps = null;
static ResultSet rs = null;
static String path = "";
static String driver="";
static String url="";
static String username="";
static String password="";
static String query="";
@SuppressWarnings({ "unchecked" })
public static void dataLoad(String path) {
JSONObject obj1 = new JSONObject();
JSONArray jsonArray = new JSONArray();
conn = DatabaseConnector.getDbConnection(driver, url, username,
password);
try {
ps = conn.prepareStatement(query);
rs = ps.executeQuery();
ArrayList<String> columnNames = new ArrayList<String>();
if (rs != null) {
ResultSetMetaData columns = rs.getMetaData();
int i = 0;
while (i < columns.getColumnCount()) {
i++;
columnNames.add(columns.getColumnName(i));
}
while (rs.next()) {
JSONObject obj = new JSONObject();
for (i = 0; i < columnNames.size(); i++) {
data.add(rs.getString(columnNames.get(i)));
{
for (int j = 0; j < data.size(); j++) {
if (data.get(j) != null) {
obj.put(columnNames.get(i), data.get(j));
}else {
obj.put(columnNames.get(i), "");
}
}
}
}
jsonArray.add(obj);
obj1.put("header", jsonArray);
FileWriter file = new FileWriter(path);
file.write(obj1.toJSONString());
file.flush();
file.close();
}
ps.close();
} else {
JSONObject obj2 = new JSONObject();
obj2.put(null, null);
jsonArray.add(obj2);
obj1.put("header", jsonArray);
}
} catch (SQLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} finally {
if (conn != null) {
try {
conn.close();
rs.close();
ps.close();
} catch (SQLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
@SuppressWarnings("static-access")
public static void main(String[] args) {
// TODO Auto-generated method stub
driver = "oracle.jdbc.driver.OracleDriver";
url = "jdbc:oracle:thin:@10.11.34.134:1521:COREMUAT";
username = "oasisusr";
password = "p#g_ay0w";
path = "D:\\VF_Polaris\\968670\\category_list1.json";
query = "select * from temp_employee";
DatabaseConnector dc = new DatabaseConnector();
dc.getDbConnection(driver,url,username,password);
DBJsonConverter formatter = new DBJsonConverter();
formatter.dataLoad(path);
}
}
以上是我的阵列
我希望以下列格式输出
输出：<?php
$distance_covered = array( '1_JAN_2017' => array('DRIVER_1' => array(2, 5, 3),'DRIVER_2' => array(3, 2, 6, 9)),
'2_JAN_2017' => array('DRIVER_1' => array(3, 9), 'DRIVER_3' => array(1, 4, 8)),
'3_JAN_2017' => array('DRIVER_4' => array(9), 'DRIVER_1' => array(2, 7, 5, 2)),
'4_JAN_2017' => array('DRIVER_1' => array(5, 3, 3, 2), 'DRIVER_4' => array(4, 9, 8, 5)),
'5_JAN_2017' => array('DRIVER_2' => array(8, 5), 'DRIVER_5' => array(3, 9, 7)),
'6_JAN_2017' => array('DRIVER_5' => array(2, 1, 7, 5), 'DRIVER_4' => array(1, 9, 6)),
'7_JAN_2017' => array('DRIVER_4' => array(5, 2, 9), 'DRIVER_3' => array(4, 1, 6)), );
这是每个驾驶员在所有行程中行驶的距离之和
我试过这样的代码，有人知道请帮助
Array ( [DRIVER_1] => 51, [DRIVER_2] => 33, [DRIVER_3] => 24, [DRIVER_4] => 67, [DRIVER_5] => 34 )答案 0 :(得分：1)
这应该有效：
$res = array();
foreach($distance_covered as $value) {
foreach($value as $key => $number) {
foreach ($number as $n) {
if (isset($res[$key])) {
$res[$key] += $n;
} else {
$res[$key] = $n;
}
}
}
}
print_r($res);
答案 1 :(得分：1)
你很亲密，但是......
$res = array ();
foreach ( $distance_covered as $value ) {
foreach ( $value as $key=> $driver ) {
if ( isset($res[$key]) == false ){
$res[$key]=0;
}
$res[$key] += array_sum($driver);
}
}
print_r($res);
第一个foreach只是简单地将数据拆分为日期。 第二个返回元素，如$ key =＆＃39; DRIVER_1＆＃39;和$ driver = array（3,9）。 如果这是您第一次遇到此驱动程序，则需要确保$ res中的元素存在，因此将其设置为0.
一旦你知道那里有一个元素，你可以使用+= array_sum($driver)位添加值的总和（在这种情况下为3和9）。 +=只是添加而不是说a=a+b，您可以说a+=b。
答案 2 :(得分：1)
这个适用于我
$res = array();
foreach($distance_covered as $value)//the array which you have given us
{
foreach($value as $key => $number) //loop over array of date
{
if(!isset($res[$key]))//check if the key exist in over defined array if no then run this
{
$res[$key] = array_sum($number);// Sum all distances of that driver
continue;//set the key and continue the foreach...
}
$res[$key] += array_sum($number);// Sum all distances of that driver
}
}
print_r($res);
die;
输出
Array
(
[DRIVER_1] => 51
[DRIVER_2] => 33
[DRIVER_3] => 24
[DRIVER_4] => 67
[DRIVER_5] => 34
)
答案 3 :(得分：1)
只遍历数组数组。
$distance_covered = array(
'1_JAN_2017' => array('DRIVER_1' => array(2, 5, 3),'DRIVER_2' => array(3, 2, 6, 9)),
'2_JAN_2017' => array('DRIVER_1' => array(3, 9), 'DRIVER_3' => array(1, 4, 8)),
'3_JAN_2017' => array('DRIVER_4' => array(9), 'DRIVER_1' => array(2, 7, 5, 2)),
'4_JAN_2017' => array('DRIVER_1' => array(5, 3, 3, 2), 'DRIVER_4' => array(4, 9, 8, 5)),
'5_JAN_2017' => array('DRIVER_2' => array(8, 5), 'DRIVER_5' => array(3, 9, 7)),
'6_JAN_2017' => array('DRIVER_5' => array(2, 1, 7, 5), 'DRIVER_4' => array(1, 9, 6)),
'7_JAN_2017' => array('DRIVER_4' => array(5, 2, 9), 'DRIVER_3' => array(4, 1, 6)), );
// Counting.
$merged = [];
foreach ($distance_covered as $day => $stats) {
foreach ($stats as $driver => $distances) {
if (!isset($merged[$driver])) {
$merged[$driver] = 0;
}
$merged[$driver] += array_sum($distances);
}
}
// Display.
echo "<pre>";
print_r($merged);
echo "</pre>";
答案 4 :(得分：0)
[讽刺的声音]我不敢相信每个人都忽略了这种复杂的基于函数的单线...
代码：（Demo）
var_export(array_map('array_sum', array_merge_recursive(...array_values($distance_covered))));
输出：
array (
'DRIVER_1' => 51,
'DRIVER_2' => 33,
'DRIVER_3' => 24,
'DRIVER_4' => 67,
'DRIVER_5' => 34,
)
*实际上，这保证比任何其他发布的答案要慢。
array_values()删除第一级关联键（日期字符串）(...)解开数组的数组，并馈入array_merge_recursive()以对值进行分组array_sum()在每个子数组上调用array_map()对子数组值求和（这只是在框外思考的一种练习。）
除此之外，没有人建议使用空合并运算符，因此我将发布如下内容：
$driver_totals = [];
foreach ($distance_covered as $daily_log) {
foreach ($daily_log as $driver => $distances) {
$driver_totals[$driver] = ($driver_totals[$driver] ?? 0) + array_sum($distances);
}
}
var_export($driver_totals);
如果您有特殊情况，只需要知道一个特定驾驶员的距离，则可以像这样调用array_column()：
$target_driver = 'DRIVER_4';
$total_distance = 0;
foreach (array_column($distance_covered, $target_driver) as $distances) {
$total_distance += array_sum($distances);
}
echo "{$target_driver} drove for a distance of {$total_distance}";
*请注意，每个日期数组中的驱动程序顺序都不重要，因为array_column()足够聪明，可以找到所需的距离子数组。
最后，如果您声明所有可能的驱动程序的白名单数组，则可以：
isset()条件代码：
$roster = ['DRIVER_6', 'DRIVER_5', 'DRIVER_4', 'DRIVER_3', 'DRIVER_2', 'DRIVER_1'];
$driver_totals = array_fill_keys($roster, 0);
foreach ($distance_covered as $daily_log) {
foreach ($daily_log as $driver => $distances) {
$driver_totals[$driver] += array_sum($distances);
}
}
var_export($driver_totals);