我有一个我试图转换为Opaleye的SQL查询。
我会简化我的代码,专注于我的问题,即如何使用Opaleye进行模糊搜索。
Haskell(有一些现有的Opaleye结构)是
namesTable :: O.Table NamesColumnWrite NamesColumnRead
namesTable = O.Table "names" (pNames Names { id = O.optional "id"
, licenseNumber = O.required "license_number"
, fullName = O.required "full_name"
})
import qualified Database.PostgreSQL.Simple as PGS
data Names' id' licenseNumber' fullName' =
Names
{ id :: id'
, licenseNumber :: licenseNumber'
, fullName :: fullName'
} deriving (Show, Eq)
namesQuery :: Query NamesColumnRead
namesQuery = queryTable NamesTable
type NamesRead = Names' Int String String
type NamesWrite = Names' (Maybe Int) String String
type NamesColumnWrite = Names' (Maybe (O.Column O.PGInt4)) (O.Column O.PGText) (O.Column O.PGText)
type NamesColumnRead = Names' (O.Column O.PGInt4) (O.Column O.PGText) (O.Column O.PGText)
getNamesByFuzzyLicenseNumber :: PGS.Connection -> String -> IO [NamesRead]
getNamesByFuzzyLicenseNumber conn licNumber = do
let query' = "SELECT id, license_number, full_name FROM get_names_by_fuzzy_license_number_fn(?)"
PGS.query conn query' [licNumber]
而且Sql是
CREATE OR REPLACE FUNCTION get_names_by_license_number_fuzzy_fn(p_license_number VARCHAR)
RETURNS TABLE
(id INT
,license_number VARCHAR
,full_name TEXT
)
AS $$
SELECT
id,
license_number,
full_name
FROM names
WHERE license_number LIKE '%' || p_license_number || '%'
$$
LANGUAGE sql;
通过'模糊搜索',我的意思是它会搜索任何一行,其中包含许可证编号,其中包含搜索参数p_license_number
的值作为子字符串。
如何将此模糊搜索查询转换为Opaleye?
这将涉及删除Sql文件并用Haskell Opaleye查询替换getNamesByLicenseNumber
。
我希望答案可能像
getNamesByLicenseNumber :: String -> Query NamesColumnRead
getNamesByLicenseNumber licNumber = proc () -> do
names <- namesQuery -< ()
restrict -< pgString licNumber .== licenseNumber (names :: NamesColumnRead)
returnA -< names
除了模糊而非严格匹配。
答案 0 :(得分:0)
我不确定你的问题究竟是什么,因为你的看起来非常好。我会改进两件事。首先,将字符串作为参数传递给like
而不是函数参数。其次,请使用.==
而不是getNamesByLicenseNumber :: QueryArr (Column PGText) NamesColumnRead
getNamesByLicenseNumber = proc licNumber -> do
names <- namesQuery -< ()
restrict -< licNumber `like` licenseNumber (names :: NamesColumnRead)
returnA -< names
。
Calendar firstDate = Calendar.getInstance();
Calendar lastDate = Calendar.getInstance();
Date startDate = firstDate.getTime();
Date endDate = lastDate.getTime();
long startTime = startDate.getTime();
long endTime = endDate.getTime();
long diffTime = endTime - startTime;
long diffDays = diffTime / (1000 * 60 * 60 * 24);
这样做你想要的吗?