我正在尝试在课堂上使用增强通道和光纤。这是一个简单的测试用例正常工作但它并不完全是我想要的。如果我将“ line:1 ”移动到“ loc:1 ”,程序会挂起(gdb显示在c ::> push之后的boost :: fibers内的spinlock(a ))。任何人都可以通过指出我做错了什么来帮助我吗?感谢。
以下是工作并生成以下内容的示例代码,
#include <iostream>
#include <boost/fiber/all.hpp>
using namespace std;
template <class T>
class Block
{
private:
typedef boost::fibers::buffered_channel<T> channel_t;
typedef boost::fibers::fiber fiber_t;
fiber_t _thread_send;
fiber_t _thread_recv;
size_t _n;
channel_t* _chan;
public:
Block(size_t n) : _n(n), _chan(nullptr) {
// >>>>>>>>>> loc:1 <<<<<<<<<<<
}
virtual ~Block() {}
void _send(channel_t *c) {
cout << __func__ << endl;
int a = 1000;
cout << "Sending: " << a << endl;
c->push(a);
}
void _recv(channel_t *c) {
cout << __func__ << endl;
int a = 0;
c->pop(a);
cout << "Received: " << a << endl;
}
void do_work() {
cout << "do_work\n";
channel_t temp{_n}; _chan = &temp; // <<<<<<<<<<<< line:1
_thread_send = boost::fibers::fiber(bind(&Block::_send, this, _chan));
_thread_recv = boost::fibers::fiber(bind(&Block::_recv, this, _chan));
_thread_send.join();
_thread_recv.join();
}
};
int main()
{
Block<int> B(2);
B.do_work();
return 0;
}
输出:
do_work
_send
Sending: 1000
_recv
Received: 1000
使用编译:
GNU/Linux 64 bit x86-64
g++ (GCC) 7.1.1 2017051
boost 1.64.0
g++ -c --std=c++14 -g -Wall -Wpedantic boost_channels.cpp -o boost_channels.o
g++ -lboost_context -lboost_fiber boost_channels.o -o boost_channels
答案 0 :(得分:1)
当您在Block构造函数中构造通道并获取指向它的指针时,指针_chan
在temp
超出范围时指向垃圾。您可以让temp
成为Block
的成员,也可以将其留在工作地点,以便转发。
更新: C ++中的括号(大括号)定义范围
Block(size_t n) : _n(n), _chan(nullptr)
//the scope of the constructor starts at this brace
{
//temp gets instantiated
channel_t temp{_n};
//assign the pointer to the object
_chan = &temp;
} //put a break point here
然后使用记忆手表来查看_chan。当你移过结束括号时,你应该看到内存在温度被破坏时变成垃圾。如果你追踪到那一点,你会看到temp遇到它的经销商。
我会将temp
留在do_work
。
答案 1 :(得分:1)
channel_t temp{_n}; _chan = &temp; // <<<<<<<<<<<< line:1
Block()
中的将无法正常工作,因为 temp 在离开Block()
的正文后超出范围,_chan将指向垃圾/释放内存
可能有两个版本:
1)将channel temp 保存为do_work()的局部变量:
template <class T>
class Block
{
private:
typedef boost::fibers::buffered_channel<T> channel_t;
typedef boost::fibers::fiber fiber_t;
fiber_t _thread_send;
fiber_t _thread_recv;
size_t _n;
public:
Block(size_t n) : _n(n) {
}
virtual ~Block() {}
void _send(channel_t *c) {
cout << __func__ << endl;
int a = 1000;
cout << "Sending: " << a << endl;
c->push(a);
}
void _recv(channel_t *c) {
cout << __func__ << endl;
int a = 0;
c->pop(a);
cout << "Received: " << a << endl;
}
void do_work() {
cout << "do_work\n";
channel_t chan{_n};
_thread_send = boost::fibers::fiber(bind(&Block::_send, this, & chan));
_thread_recv = boost::fibers::fiber(bind(&Block::_recv, this, & chan));
_thread_send.join();
_thread_recv.join();
}
};
2)将频道 temp 保留为Block&lt;&gt;的成员变量:
template <class T>
class Block
{
private:
typedef boost::fibers::buffered_channel<T> channel_t;
typedef boost::fibers::fiber fiber_t;
fiber_t _thread_send;
fiber_t _thread_recv;
channel_t _chan;
public:
Block(size_t n) : _chan(n) {
}
virtual ~Block() {}
void _send(channel_t *c) {
cout << __func__ << endl;
int a = 1000;
cout << "Sending: " << a << endl;
c->push(a);
}
void _recv(channel_t *c) {
cout << __func__ << endl;
int a = 0;
c->pop(a);
cout << "Received: " << a << endl;
}
void do_work() {
cout << "do_work\n";
_thread_send = boost::fibers::fiber(bind(&Block::_send, this, & _chan));
_thread_recv = boost::fibers::fiber(bind(&Block::_recv, this, & _chan));
_thread_send.join();
_thread_recv.join();
}
};
两个版本都会生成:
do_work
_send
Sending: 1000
_recv
Received: 1000
答案 2 :(得分:0)
好的,将channel_t声明为成员可以正常工作。我猜它指的是垃圾。另外我了解到boost同步原语不喜欢std :: move(ed)。
感谢各位帮忙。