Question

我在将表连接到SQL中的子字符串中的结果时遇到问题。

以下是我的发言：

SELECT a.MEASR_COMP_ID
     , f.D1_USAGE_ID
     , f.SCH_SELECTION_DT
     , g.MEASR_COMP_ID
     , g.MSRMT_VAL
     , i.USAGE_ID
     , SUBSTR(dbms_lob.substr(i.USG_DATA_AREA, 4000, 1)
              ,INSTR(dbms_lob.substr(i.USG_DATA_AREA, 4000, 1)
              ,'<startReading>') + LENGTH('<startReading>'), 8)
             "Start Reading"
     , SUBSTR(dbms_lob.substr(i.USG_DATA_AREA, 4000, 1)
     , INSTR(dbms_lob.substr(i.USG_DATA_AREA, 4000, 1)
     , '<endReading>') + LENGTH('<endReading>'), 8) as "End Reading"
FROM C1_USAGE I
   , CISADM.D1_USAGE@CCBMDM f
   , CISADM.D1_MSRMT@CCBMDM g
   , CISADM.D1_USAGE_PERIOD_SQ@CCBMDM a
WHERE f.USG_EXT_ID = i.USAGE_ID AND
      f.D1_USAGE_ID = a.D1_USAGE_ID AND
      a.MEASR_COMP_ID = g.MEASR_COMP_ID AND
      i.USAGE_ID = '119993413555' AND
      SUBSTR(dbms_lob.substr(i.USG_DATA_AREA, 4000, 1)
             ,INSTR(dbms_lob.substr(i.USG_DATA_AREA, 4000
             ,1), '<endReading>') + LENGTH('<endReading>'), 8)
             as "End Reading" = g.MSRMT.VAL

Answer 1

应该没问题，除非您应该从条件中删除as "End Reading"部分，并考虑使用正确的ANSI样式JOIN语法而不是这种困惑的语法

将表连接到SQL中的子字符串

1 个答案: