Question

我制作了一个基本的Android应用程序，注册活动和登录活动，我使用免费的网络托管（000webhost）数据库。

一切正常，但是当我使用注册活动表单（电子邮件和密码）注册时，它不会将用户凭据保存到数据库中。它甚至没有显示错误。我已经检查了代码，到目前为止没有错误。

<?php
$con = mysqli_connect("host", "database user", "password", "database 
name");

$email = $_POST["email"];
$password = $_POST["password"];

$statement = mysqli_prepare($con, "INSERT INTO database name (email, 
password) VALUES (?, ?)");
mysqli_stmt_bind_param($statement, "ss", $email, $password);
mysqli_stmt_execute($statement);

$response = array();
$response["success"] = true;

echo json_encode($response);
?>









public class RegisterActivity extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_register);

    final EditText etEmail = (EditText) findViewById(R.id.etEmail);
    final EditText etPassword = (EditText) findViewById(R.id.etPassword);
    final Button bRegister = (Button) findViewById(R.id.bRegister);

    bRegister.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            final String email = etEmail.getText().toString();
            final String password = etPassword.getText().toString();

            Response.Listener<String> responseListener = new Response.Listener<String>(){

                @Override
                public void onResponse(String response) {
                    try {
                        JSONObject jsonResponse = new JSONObject(response);
                        boolean success = jsonResponse.getBoolean("success");

                        if (success){
                            Intent intent = new Intent(RegisterActivity.this, LoginActivity.class);
                            RegisterActivity.this.startActivity(intent);
                        } else {
                            AlertDialog.Builder builder = new AlertDialog.Builder(RegisterActivity.this);
                            builder.setMessage("Register Failed")
                            .setNegativeButton("Retry", null)
                            .create()
                            .show();
                        }

                    } catch (JSONException e) {
                        e.printStackTrace();
                    }

                }
            };




            RegisterRequest registerRequest = new RegisterRequest(email, password, responseListener);
            RequestQueue queue = Volley.newRequestQueue(RegisterActivity.this);
            queue.add(registerRequest);

        }
    });
}

}

public class RegisterRequest extends StringRequest {

private static final String REGISTER_REQUEST_URL = "";
private Map<String, String> params;

public RegisterRequest(String email, String password, Response.Listener<String> listener){
    super(Method.POST, REGISTER_REQUEST_URL, listener, null);
    params = new HashMap<>();
    params.put("email", email);
    params.put("password", password);
}

@Override
public Map<String, String> getParams() {
    return params;
}

}

Answer 1

注意区别：你有一个数据库服务器。在该服务器上是一个数据库（或多个）。这样的数据库可以用于某些网站/项目。在该数据库中有几个表。

在此表中存储信息。

您的插入查询要插入“数据库名称” 你应该插入某个表

Answer 2

除非您的表名是＆＃34;数据库名称＆＃34;，否则这就是它无法运作的原因。另外，我不认为mySQL允许表名中有空格，但我可能错了。

$statement = mysqli_prepare($con, "INSERT INTO database name (email, 
password) VALUES (?, ?)");

应替换为

$statement = mysqli_prepare($con, "INSERT INTO table_name (email, 
password) VALUES (?, ?)");

我的PHP注册表单不会将数据发送到数据库

2 个答案: