我正在使用C ++编写ATM机器代码。我知道最好使用二进制文件和类，以便每个帐户在文件中具有完全相同的大小，即使它是空的。我正在寻找一些非常简单的东西。
我在解析.txt文件中的逗号分隔值时遇到问题。有时候我会得到价值，有时候我只得到第一个价值。我花了好几天才弄清楚它的解决方案。我搜索了互联网和stackoverflow几乎每个答案都使用了矢量或其他东西。
我没有使用strcmp进行数组比较，而是创建了自己的函数来比较字符和字符。
从代码的外观来看，似乎我做了很多，只需要一点点推动。请仔细看看我的代码，让我知道我错在哪里。我想消除语义错误！并修改以下代码以实现预期结果。
#include<iostream>
#include<conio.h>
#include<fstream>
#include<cstring>
#include<string>
#include<sstream>
#include<stdlib.h>
using namespace std;
void checkBalance();
void createAccount();
void deposit();
void withdraw();
void transfer();
void login();
void mainScreen();
void menuScreen();
// For file handling
void saveAccountToFile();
bool checkAccountExists(char*);
void loadAccount(char *);
void loadBeneficiary(char*);
bool compare(char *, char *);
const char * FILE_NAME = "accounts.txt";
char username[50];
char pin[5];
double balance = 0.0;
// Beneficiary Variables
char b_username[50];
char b_pin[5];
double b_balance = 0.0;
void menuScreen()
{
char opt;
do {
system("cls");
cout << "\n\n\t\t CMD - ATM";
cout << "\n\n\tMENU";
cout << "\n\n\t01. Check Balance";
cout << "\n\n\t02. Withdraw";
cout << "\n\n\t03. Deposite";
cout << "\n\n\t04. Transfer to Another account";
cout << "\n\n\t05. Logout";
opt = _getch();
switch (opt)
{
case '1':
checkBalance();
break;
case '2':
withdraw();
break;
case '3':
deposite();
break;
case '4':
transfer();
case '5':
cout << "\n\nThanks for using CMD ATM. Press any key to exit...";
_getch();
exit(1);
default:
cout << "\a\n\nIncorrect input. Press any key to try agian!";
_getch();
}
} while (opt != '5');
}
void mainScreen()
{
char opt;
do {
system("cls");
cout << "\n\n\t\t CMD - ATM";
cout << "\n\n\tMENU";
cout << "\n\n\t01. Create Account";
cout << "\n\n\t02. Login";
cout << "\n\n\t03. Exit";
opt = _getch();
switch (opt)
{
case '1':
createAccount();
break;
case '2':
login();
break;
case '3':
exit(1);
default:
cout << "\a\n\nIncorrect input. Press any key to try agian!";
_getch();
}
} while (opt != '3');
}
void saveAccountToFile() {
ofstream outFile;
outFile.open(FILE_NAME, ios::app);
if (outFile.is_open()) {
outFile << username << ',' <<
pin << ',' << balance << "\n";
}
outFile.close();
}
bool checkAccountExists(char * userName)
{
int i = 0;
char temp[50] = {'0'};
ifstream inFile;
string line;
inFile.open(FILE_NAME);
if (inFile.is_open()) {
while (getline(inFile, line)) {
stringstream ss(line);
string value;
while (getline(ss, value, ',')) {
if (i == 0) {
strcpy(temp,value.c_str());
if(compare(userName, temp)){
cout << "closing";
getchar();
inFile.close();
return true;
}
i = 1;
}
else if (i == 1) {
i = 2;
}
else if (i == 2) {
i = 0;
}
}
}
inFile.close();
}
return false;
}
void loadAccount(char * userName)
{
int i = 0;
ifstream inFile;
string line;
inFile.open(FILE_NAME);
if (inFile.is_open()) {
while (getline(inFile, line)) {
stringstream ss(line);
string value;
while (getline(ss, value, ',')) {
if (i == 0) {
strcpy(username, value.c_str());
i = 1;
}
else if (i == 1) {
strcpy(pin, value.c_str());
i = 2;
}
else if (i == 2) {
balance = atof(value.c_str());
i = 0;
}
if(compare(username,userName))
{
inFile.close();
break;
}
}
}
inFile.close();
}
}
void loadBeneficiary(char * userName)
{
int i = 0;
ifstream inFile;
string line;
inFile.open(FILE_NAME);
if (inFile.is_open()) {
while (getline(inFile, line)) {
stringstream ss(line);
string value;
while (getline(ss, value, ',')) {
if (i == 0) {
strcpy(b_username, value.c_str());
i = 1;
}
else if (i == 1) {
strcpy(b_pin, value.c_str());
i = 2;
}
else if (i == 2) {
b_balance = atof(value.c_str());
i = 0;
}
if(strcmp(b_username, userName)){
inFile.close();
break;
}
}
}
inFile.close();
}
}
void login()
{
char tempName[50];
char tempPin[5];
cout << "\n\nEnter user name: ";
cin.getline(tempName, sizeof(tempName));
if (checkAccountExists(tempName)) {
cout << "\n\nEnter user pin: ";
cin.getline(tempPin,sizeof(tempPin));
loadAccount(tempName);
if (compare(tempPin, pin)) {
cout << "\n\nLog in successfull!";
cout << "\n\nPress any key to continue...";
_getch();
menuScreen();
}else {
cout << "User name or pin incorrect!";
_getch();
}
}
else {
cout << "\n\nRecord not found. Press any key to continue...";
_getch();
}
}
void checkBalance()
{
system("cls");
cout << "\n\n\tUser name = " << username;
cout << "\n\n\tBalance = " << balance;
_getch();
}
bool compare(char * msg1, char * msg2){
int count = 0;
int size = sizeof(msg1);
if(sizeof(msg2) == size){
for(int i = 0; i < size; i++){
if(msg1[i]==msg2[i]){
count++;
}
}
if(count == size)
return true;
}
return false;
}
int main(int argc, char** argv) {
mainScreen();
getchar();
return 0;
}
TXT FILE
jhon,5155,99999.99
bot,4414,232323
theta,2111,34234
答案 0 :(得分：1)
关于如何简化阅读循环，如何
while (getline(inFile, line)) {
stringstream ss(line);
string value;
getline(ss, value, ',');
string name = value;
getline(ss, value, ',')
string pin = value;
getline(ss, value)
double balance = stod(value);
// Now use the name, pin and balance some way...
}
当你只需要这个名字时，你不需要进行第二次和第三次getline通话，只需要第一次。
还可以考虑使用结构来存储名称，引脚和平衡，然后使用container（例如vector）来存储结构。
同样以简洁的名义，我建议你只阅读文件一次。然后遍历向量以找到所需的数据。
答案 1 :(得分：0)
以下是不使用stringstream
while(getline(inFile,line,',')){
strcpy(username, line.c_str());
getline(inFile,line,',');
strcpy(pin, line.c_str());
getline(inFile,line,'\n');
balance = atof(line.c_str());
if(compare(username,userName)){
inFile.close();
break;
}else
continue;
}