Question

我使用PHP访问SQL服务器数据库，我有2个数字存储为PHP变量。

例如，一个变量是10，另一个变量是15。

我需要输出一个“缺失”文档列表，即某个列col1不包含10和15之间的数字的行。

示例：

变量：

$start = 10
$end = 15

仅使用SQL的所需结果：

result
------
11
13
15

Answer 1

如果您没有数字/统计表，则可以使用与LEFT JOIN

一致的临时计数表

示例

Declare @R1 int = 10 Declare @R2 int = 15 Select Result= N From ( Select Top (@R2-@R1+1) N=@R1-1+Row_Number() Over (Order By (Select null)) From master..spt_values n1,master..spt_values n2 ) A Left Join YourTable B on A.N = B.[col1] Where B.[col1] is null

<强>返回

Result 11 13 15

Answer 2

您可以通过不同的方式实现这一点，一种方法是生成一个计数表并按左下方进行连接：

Declare @start int = 10
Declare @end int = 15

;With CTE_Numbers as (
    Select top (@end - @start+1) RowN = @start + Row_number() over (order by (SELECT NULL)) -1
        from master..spt_values s1, master..spt_values s2
        ) 
        Select c.RowN as Result from CTE_Numbers c 
            left join yourtable t
            on c.RowN = t.col1
            where t.col1 is null

Answer 3

    declare  @t table (col1 int);
    insert into @t values
    (2),
    (4),
    (6),
    (8),
    (10),
    (12),
    (14),
    (16),
    (18),
    (20)

    declare @start int = 10,
            @end int = 15;

    with nums as
    (
    select n
    from
        (
        select row_number() over(order by getdate()) n
        from sys.all_columns c1 cross join sys.all_columns c2
        ) t
    where n between @start and @end
    )

    select *
    from nums
    where not exists (select col1 from @t t where nums.n = t.col1);

Answer 4

我会使用dbo.Numbers(Numbers PK) table（reference #2）并跟随查询：

DECLARE @start INT = 10, @end INT = 15

SELECT x.Col1
FROM dbo.SourceTable x
WHERE x.Col1 >= @start AND x.Col1 <= @end
AND NOT EXISTS (
    SELECT * FROM dbo.Numbers n
    WHERE n.Number >= @start AND n.Number <= @end
    AND n.Number = x.Col1
)

在SQL Server中查找2个变量之间缺少的行

4 个答案: