Question

我有一个表，其中包含由类标记的行。这些行应该是斑马条纹。需要注意的是，它们并不总是连续的。

我尝试按表和类名匹配，但最终结果总是不正确。发生的事情是条带化将在表级应用，然后仅在具有类的行上启用。

我需要做些什么才能让这项工作像我想要的那样？

脚本

function FormatTable()
{
   $("#TableId .arbitrarySelector:nth-child(2n+1)" ).addClass('anotherEquallySpecialRow')
}

HTML

<table id="TableId" onclick="FormatTable()">
    <tr class="arbitrarySelector">
        <td><div class="space">Should be Changed and is</div></td>
    </tr>
    <tr class="arbitrarySelector">
        <td><div class="space">Should Not be Changed and is Not</div></td>
    </tr>
    <tr class="arbitrarySelector">
        <td><div class="space">Should be Changed and is</div></td>
    </tr>
    <tr>
        <td><div class="space"></div></td>
    </tr>
    <tr class="arbitrarySelector">
        <td><div class="space">Should NOT be changed but is</div></td>
    </tr>
    <tr>
        <td><div class="space"></div></td>
    </tr>
    <tr class="arbitrarySelector">
        <td><div class="space">Should be Changed and is</div></td>
    </tr>
    <tr>
        <td><div class="space"></div></td>
    </tr>
    <tr>
        <td><div class="space"></div></td>
    </tr>
    <tr class="arbitrarySelector">
        <td><div class="space">Should Not be Changed and is Not</div></td>
    </tr>
    <tr class="arbitrarySelector">
        <td><div class="space">Should be Changed and is</div></td>
    </tr>
    <tr class="arbitrarySelector">
        <td><div class="space">Should Not be Changed and is Not</div></td>
    </tr>
</table>

Answer 1

你可能会让这太难了。如果你想做斑马条纹，为什么不使用类似:odd selector的东西并改变类依赖。像这样......

// Add zebra striping.
$('.arbitrarySelector:odd').addClass('zebra');

然后CSS就像......

.zebra 
{
    background-color: #dddddd;
}

试图在表格中对Zebra条带化任意行

1 个答案: