Question

var expression = "[AccNum]==true&&[AccNum]==[ARID]&&[AccNum]==aaaa || [ARID]!=true&&[DOB]&gt;[ARID] || [DOB]&gt;bbb&&[DOS]&gt;=[ARID]&&[DOS]&lt;[Gender]&&[66642]&lt;=cccc&&[66642] In (ddd,fff,ggg) || [FirstName] NotIn (hhh,jjj,kkk)&&[FirstName] StartsWith lll || [Gender] EndsWith mmm";

我需要将此表达式拆分为数组，如

var arr = [ "[AccNum]==true","&&", "[AccNum]==[ARID]", "&&", "[AccNum]==aaaa", "||", "[ARID]!=true", "&&", "[DOB]&gt;[ARID]", "||", "[DOB]&gt;bbb", "&&", "[DOS]&gt;=[ARID]", "&&", "[DOS]&lt;[Gender]", "&&", "[66642]&lt;=cccc", "&&", "[66642] In (ddd,fff,ggg)", "||", "[FirstName] NotIn (hhh,jjj,kkk)", "&&", "[FirstName] StartsWith lll", "||", "[Gender] EndsWith mmm" ]

这里的键是＆＃34;＆amp;＆amp;＆＃34;和＆＃34; ||＆＃34;但是我也需要数组中的键。

Answer 1

＆＃13;

var expression = "[AccNum]==true&&[AccNum]==[ARID]&&[AccNum]==aaaa || [ARID]!=true&&[DOB]&gt;[ARID] || [DOB]&gt;bbb&&[DOS]&gt;=[ARID]&&[DOS]&lt;[Gender]&&[66642]&lt;=cccc&&[66642] In (ddd,fff,ggg) || [FirstName] NotIn (hhh,jjj,kkk)&&[FirstName] StartsWith lll || [Gender] EndsWith mmm";

var converted = expression
                .split(/(&&|\|\|)/)
                .map(item => item.trim());

console.log(converted)

＆＃13;

括在括号中的RegEx分隔符将推送数组中的分隔符以及项目，这要归功于：https://stackoverflow.com/a/12002085/3499595

修剪每个项目的地图，删除空格。

Answer 2

试试这个：

var expression = "[AccNum]==true&&[AccNum]==[ARID]&&[AccNum]==aaaa || [ARID]!=true&&[DOB]&gt;[ARID] || [DOB]&gt;bbb&&[DOS]&gt;=[ARID]&&[DOS]&lt;[Gender]&&[66642]&lt;=cccc&&[66642] In (ddd,fff,ggg) || [FirstName] NotIn (hhh,jjj,kkk)&&[FirstName] StartsWith lll || [Gender] EndsWith mmm";
var splitArray = expression.split(/(&&|\|\|)/g);

将表达式拆分为具有多个键的数组，并在数组中包含键

2 个答案: