我目前的实施方案是否有单线代替?
Top Level
-- Sub Level
--- Folder
-- Sub Level
--- Folder
.
.
.
要获得每个-- Folder
中的-- Sub Level
,我有以下内容:
dir_ = '/path/to/Top Level'
sub_lvl = [os.path.join(dir_, sub) for sub in os.listdir(dir_)]
# "folder" is always a fixed name
folders = [os.path.join(sub, "folder") for sub in sub_lvl]
答案 0 :(得分:1)
os.path.join
采用任意数量的字符串。你应该检查项目是否是一个文件夹:
sub_lvl = [os.path.join(dir_, sub, "folder") for sub in os.listdir(dir_) if os.path.isdir(os.path.join(dir_,sub))]
答案 1 :(得分:1)
你去了:
folders = [os.path.join(os.path.join(dir_, sub), "folder") for sub in os.listdir(dir_)]