Question

我在尝试使用正则表达式和美丽的汤时遇到了一些麻烦。

我的HTML如下：

[<strong>See the full calendar</strong>, <strong>See all events</strong>, <strong>See all committee meetings</strong>, <strong>526 spaces</strong>, <strong>89 spaces</strong>, <strong>53 spaces</strong>, <strong>154 spaces</strong>, <strong>194 spaces</strong>, <strong>See all news releases</strong>]
[<strong>See the full calendar</strong>, <strong>See all events</strong>, <strong>See all committee meetings</strong>, <strong>526 spaces</strong>, <strong>89 spaces</strong>, <strong>53 spaces</strong>, <strong>154 spaces</strong>, <strong>194 spaces</strong>, <strong>See all news releases</strong>]

我想要的只是强标签之间的空格数。

我尝试过使用：

print(soup.find_all(re.compile("\d\d\d\s[a-zA-Z]{6}|(strong)")))

但是，这会返回print(soup.find_all('strong'))所做的所有事情。

有谁知道我哪里出错了？

Answer 1

如果我理解正确，您可以使用text的{{1}}属性，并传递已编译的正则表达式模式：

soup.find_all

输出：

import re
spaces = []
for tag in content.find_all(text=re.compile("\d+(?= spaces)")):
    spaces.append(int(tag.string.split()[0]))

print(spaces)

Answer 2

首先找到所有强标签

strong_tags = soup.find_all('strong')
spaces_in_tags = {}

# Afterwards iterate over the tags.. Then do either

for strong in strong_tags:
    # 1. (EDIT add \s+ so multiple spaces between words will count as 1 space)
    number_of_spaces = len(re.findall('\s+', strong))
    # 2.
    number_of_spaces2 = len(strong.split())-1

    # Then add them do a dictionary/list whatever suits your need
    # For example to have the string as the key parameter in a dictionary
    spaces_in_tags[strong] = number_of_spaces

使用正则表达与美丽的汤

2 个答案: