Array
(
[25p] => Array
(
[0] => Array
(
[id] => 353
[label] => C81
[casting] => 21 Mar 2017
[data] => Array
(
[0] => Array
(
[x] => 1
[y] => 6.220000
)
[1] => Array
(
[x] => 2
[y] => 10.220000
)
[2] => Array
(
[x] => 7
[y] => 21.440000
)
[3] => Array
(
[x] => 28
[y] => 30.780000
)
)
)
[1] => Array
(
[id] => 354
[label] => C82
[casting] => 21 Mar 2017
[data] => Array
(
[0] => Array
(
[x] => 1
[y] => 8.000000
)
[1] => Array
(
[x] => 3
[y] => 20.890000
)
[2] => Array
(
[x] => 6
[y] => 30.670000
)
[3] => Array
(
[x] => 7
[y] => 32.555000
)
[4] => Array
(
[x] => 28
[y] => 51.110000
)
)
)
[2] => Array
(
[id] => 355
[label] => C83
[casting] => 21 Mar 2017
[data] => Array
(
[0] => Array
(
[x] => 1
[y] => 7.110000
)
[1] => Array
(
[x] => 3
[y] => 19.780000
)
[2] => Array
(
[x] => 6
[y] => 23.560000
)
[3] => Array
(
[x] => 7
[y] => 32.225000
)
[4] => Array
(
[x] => 15
[y] => 38.890000
)
)
)
[age] => Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 6
[4] => 7
[5] => 15
[6] => 28
)
)
)
我想基于[age]值创建一个表作为标题。我设法创建表但问题是，我的数据没有正确放置。 [age]基于[data][x]值的唯一展平列表。从数组数据中，C83不应包含2D数据，因为没有[data][x] = 2
+---------------+----------+-----------+-----------+-----------+-----------+-----+-----+
| Monitor Label | 1D | 2D | 3D | 6D | 7D | 15D | 28D |
+---------------+----------+-----------+-----------+-----------+-----------+-----+-----+
| C81 | 6.220000 | 10.220000 | 21.440000 | 30.780000 | |
| |
| C82 | 8.000000 | 20.890000 | 30.670000 | 32.555000 | 51.110000 |
| |
| C83 | 7.110000 | 19.780000 | 23.560000 | 32.225000 | 38.890000 |
| |
+---------------+----------+-----------+-----------+-----------+-----------+-----+-----+
下面是我生成上表的代码
//test creating HTML
foreach($graph as $grade => $data )
{
echo '<strong>'.strtoupper($grade).'</strong></br>';
//start the table for each grade
echo '<table border=1>';
echo '<thead>';
echo '<tr>';
echo '<th>Monitor Label</th>';
for($i=0;$i < count($data['age']);$i++)
{
echo '<th>'.$data['age'][$i].'D</th>';
}
echo '</tr>';
echo '</thead>';
echo '<tbody>';
for ($i=0;$i < count($data)-1; $i++)
{
echo '<tr>';
echo '<td>'.$data[$i]['label'].'</td>';
foreach($data[$i]['data'] as $x)
{
echo '<td>'.$x['y'].'</td>';
}
echo '</tr>';
}
echo '</tbody>';
echo '</table>';
}
部分[data][y]应该丢失，我想用 - （破折号）或#NA替换它，但它只填充表格列。
如果有人对数据感兴趣，这里是实际的序列化数据
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答案 0 :(得分：0)
您可以尝试以下代码，其中i循环遍历年龄并检查数据中的“x”值
//test creating HTML
foreach($graph as $grade => $data )
echo '<strong>'.strtoupper($grade).'</strong></br>';
//start the table for each grade
echo '<table border=1>';
echo '<thead>';
echo '<tr>';
echo '<th>Monitor Label</th>';
for($i=0;$i < count($data['age']);$i++)
{
echo '<th>'.$data['age'][$i].'D</th>';
}
echo '</tr>';
echo '</thead>';
echo '<tbody>';
for ($i=0;$i < count($data)-1; $i++)
{
echo '<tr>';
echo '<td>'.$data[$i]['label'].'</td>';
for($j=0;$j < count($data['age']);$j++){
foreach($data[$i]['data'] as $x)
{
if($x['x'] == $data['age'][$j])
echo '<td>'.$x['y'].'</td>';
else
echo '<td> #NA </td>';
}
}
echo '</tr>';
}
echo '</tbody>';
echo '</table>';
}
答案 1 :(得分：0)
您需要在所有count($data['age']数组上循环$data[$i]['data']次迭代，但每次检查是否存在具有该出现的数组。如果是，则打印['y']号码，如果不是，则在表格列中打印-或N/A。
替换
foreach($data[$i]['data'] as $x)
{
echo '<td>'.$x['y'].'</td>';
}
只会循环['data']实际存在的次数
用
for ($y=0; $y < count($data['age']; $y++) {
if ( isset($data[$i]['data'][$y]) ) {
if ( $data[$i]['data'][$y]['x'] == $data['age'][$i] ) {
echo '<td>'.$data[$i]['data'][$y]['y'].'</td>';
} else {
echo '<td>N/A</td>';
}
} else {
echo '<td>N/A</td>';
}
}
答案 2 :(得分：0)
我问周围，最后得到了答案和解决方案。
基本上，重新排列和简化数组以获得[x]和[y]值。然后将[x]添加到自己的数组中。之后，使用[x]作为数组键来循环数据，以获得[y]值。
我已经重新安排我的数组以简化这个过程和我的数组