如何初始化dvd1?
C:\Users\SuperUser\Google Drive>g++ -o a Question1.cpp
Question1.cpp:在函数' int main()':
Question1.cpp:39:76:错误:在C ++ 98' dvd1'必须由构造函数初始化,而不是由' {...}'
初始化dvd dvd1 = {" Zombie"," BBC"," James","英语"," Alw&#34 ;,2012,20170601,20170630};
#include <iostream>
#include <string>
using namespace std;
class dvd
{
string movieName,movieProdComp,movieLeadActor,movieLanguage,renterName;
int releaseYear,rentDate,returnDate;
public:
dvd(string mn,string mpc,string mla,string ml, string rn,int ry,int rd,int retd);
void print();
};
dvd::dvd(string mn,string mpc,string mla,string ml, string rn, int ry,int rd,int retd){
movieName=mn;
movieProdComp=mpc;
movieLeadActor=mla;
movieLanguage=ml;
renterName=rn;
releaseYear=ry;
rentDate=rd;
returnDate=retd;
}
void dvd::print(){
cout<<"Movie:"<<movieName<<endl;
cout<<"Production:"<<movieProdComp<<endl;
cout<<"Starring:"<<movieLeadActor<<endl;
cout<<"Language:"<<movieLanguage<<endl;
cout<<"Rented By:"<<renterName<<endl;
cout<<"Released:"<<releaseYear<<endl;
cout<<"Rent Date:"<<rentDate<<endl;
cout<<"Return Date:"<<returnDate<<endl;
}
int main(){
dvd();
dvd dvd1 = {"Zombie","BBC","James","English","Alw",2012,20170601,20170630};
dvd1.print();
}
答案 0 :(得分:5)
dvd
是非aggregate type,无法使用支撑的初始化程序进行初始化,直到支持list initialization的C ++ 11。 (更准确地说,您尝试做的是复制列表初始化。)
对于C ++ 98,您可以编写
dvd dvd1 ("Zombie","BBC","James","English","Alw",2012,20170601,20170630);
dvd dvd1 = dvd("Zombie","BBC","James","English","Alw",2012,20170601,20170630);
在C ++ 98中,只有当dvd dvd1 = {...};
为聚合类型时才可以使用aggregate initialization;对于这种情况,dvd
具有用户定义的构造函数,然后不是。
答案 1 :(得分:2)
这称为list initialization,对于非聚合类型,它仅在C ++ 11中受支持:
dvd dvd1 = {"Zombie","BBC","James","English","Alw",2012,20170601,20170630};
对于C ++ 98,你可能想稍微改一下,像往常一样调用构造函数:
dvd dvd1("Zombie","BBC","James","English","Alw",2012,20170601,20170630);