显示从数据库中选择的下拉值（iemysql）

Question

我已将选择下拉菜单中的苹果值保存到mysql中。 现在在编辑页面中，我想显示相应的值。 但我似乎没有把它弄好

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<?php $food = $mysqli->real_escape_string($_POST['food']); ?>

<select id="food" required name="food" >

    <option value="" disabled selected>Select a Food</option>
    <option value="apple" <?php if($food == apple) 
    echo "selected='selected'"; ?>Apple</option>
    
    <option value="kiwi" <?php if($food == kiwi) 
    echo "selected='selected'"; ?>Kiwi</option>
</select></div>

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Answer 1

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<select id="food" required name="food" >

    <option value="" >Select a Food</option>
    <option value="apple" <?php if($food == "apple") 
    echo "selected='selected'"; ?>Apple</option>
    
    <option value="kiwi" <?php if($food == "kiwi") 
    echo "selected='selected'"; ?>Kiwi</option>
</select></div>

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Answer 2

single应附加double引号或if($food == 'apple')引号<select id="food" required name="food" > <option value="" disabled selected>Select a Food</option> <option value="apple" <?php if($food == 'apple') echo "selected='selected'"; ?>Apple</option> <option value="kiwi" <?php if($food == 'kiwi') echo "selected='selected'"; ?>Kiwi</option> </select></div>

$query = Doctrine_Query::create()
  ->from('attendanceRecord a')
  ->whereIn('a.employeeId', $employeeId);