Question

我尝试使用java将此代码转换为XML文件。输出XML文件为空。

这是java代码： -

import java.io.File;

import javax.xml.namespace.QName;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.TransformerConfigurationException;
import javax.xml.transform.stream.StreamResult;

import org.apache.xerces.xs.XSModel;
import org.apache.xmlbeans.impl.inst2xsd.util.Element;
import org.w3c.dom.Document;

import jlibs.xml.sax.XMLDocument;
import jlibs.xml.xsd.XSContentModel;
import jlibs.xml.xsd.XSInstance;
import jlibs.xml.xsd.XSParser;

public class xsdconv {

     public static void main(String[] pArgs) {
            try {
                String filename ="C:\\Users\\Admin\\Desktop\\out.xsd";
                // instance.

                final Document doc = loadXsdDocument(filename);

                            //Find the docs root element and use it to find the targetNamespace
                final org.w3c.dom.Element rootElem = doc.getDocumentElement();
                String targetNamespace = null;
                if (rootElem != null && rootElem.getNodeName().equals("xsd:schema")) 
                           {
                    targetNamespace = rootElem.getAttribute("root");
                }


                            //Parse the file into an XSModel object
                XSModel xsModel = new XSParser().parse(filename);

                            //Define defaults for the XML generation
                XSInstance instance = new XSInstance();
                instance.minimumElementsGenerated = 1;
                instance.maximumElementsGenerated = 1;
                instance.generateDefaultAttributes = true;
                instance.generateOptionalAttributes = true;
                instance.maximumRecursionDepth = 0;
                instance.generateAllChoices = true;
                instance.showContentModel = true;
                instance.generateOptionalElements = true;

                            //Build the sample xml doc
                            //Replace first param to XMLDoc with a file input stream to write to file
                QName rootElement = new QName(targetNamespace, "root");
                XMLDocument sampleXml = new XMLDocument(new StreamResult("C:/Users/Admin/Desktop/out.xml"), true, 4, null);

            } catch (TransformerConfigurationException e) 
                    {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }

        public static Document loadXsdDocument(String inputName) {
            final String filename = inputName;

            final DocumentBuilderFactory factory = DocumentBuilderFactory
                    .newInstance(); 
            factory.setValidating(false); 
            factory.setIgnoringElementContentWhitespace(true);
            factory.setIgnoringComments(true);
            Document doc = null;

            try {
                final DocumentBuilder builder = factory.newDocumentBuilder();
                final File inputFile = new File(filename);
                doc = builder.parse(inputFile);
                System.out.println(filename);
            } catch (final Exception e) {
                e.printStackTrace();
                // throw new ContentLoadException(msg);
            }

            return doc;
        }
}

示例XSD文件为： -

<?xml version="1.0" encoding="UTF-8"?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <xsd:element name="root">
    <xsd:complexType>
      <xsd:sequence>
        <xsd:element name="header" maxOccurs="unbounded" type="xsd:normalizedString"/>
        <xsd:element name="row" maxOccurs="unbounded" type="xsd:string"/>
      </xsd:sequence>
    </xsd:complexType>
  </xsd:element>
</xsd:schema>

所以我想从中提取标题和行信息。它正在创建空白的XML文件。我在这段代码中缺少什么？我认为解析工作正常。

修改这是XSD文件中的信息，我希望XSD文件像这样创建XML。

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<root>
  <header>Symbol</header>
    <row>NIFTY 50</row>
    <row>LUPIN</row>
    <header>Open</header>
    <row>9,670.35</row>
    <row>1,082.90</row>
</root>

Answer 1

您还没有填充XML文件。您可以在以下行后添加：

XMLDocument sampleXml = new XMLDocument(new StreamResult("C:/Users/Admin/Desktop/out.xml"), true, 4, null);

类似的东西：

sampleXml.startDocument();{
    sampleXml.startElement("root");{
        sampleXml.addElement("header", "Symbol");
        sampleXml.addElement("row","NIFTY 50");
        sampleXml.addElement("row","LUPIN");
        sampleXml.addElement("header", "Open");
        sampleXml.addElement("row","9,670.35");
        sampleXml.addElement("row","1,082.90");
    }
    sampleXml.endElement("root");
}
sampleXml.endDocument();

或您喜欢的任何其他内容作为默认设置。

XML无法正确创建：内容为空

1 个答案: