Question

我遇到的问题是API给了一个长字符串，其中包含需要分解为对象的多个项目。以下是字符串的示例：

"Child 1 First Name: Ali\nChild 1 Gender: Female\nChild 1 Hair Color: Blonde\nChild 1 Hair Style: Wavy\nChild 1 Skin Tone: Tan\nChild 2 First Name: Morgan \nChild 2 Gender: Female\nChild 2 Hair Color: Brown\nChild 2 Hair Style: Ponytail\nChild 2 Skin Tone: Light\nRelationship 1 to 2: Brother\nRelationship 2 to 1: Brother\n"

正在使用\n将所有内容分成多行。该字符串是API发送的较大对象的一个属性。出于某种原因，当我尝试使用.split方法时（如下面的完整代码），我需要使用JSON.stringify才能让我的功能开始工作。

这是我的完整代码：

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let rawNoteData = order.customer.note;
let data = JSON.stringify(rawNoteData);

let foo = data.split("\n").reduce(function(obj, str, index) {
  let strParts = str.split(":");
  obj[strParts[0].replace(/\s+/g, '')] = strParts[1];
  return obj;
}, {});

console.log(foo);

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这会创建看起来很疯狂的对象：

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{'"Child1FirstName': ' Arabelle\\nChild 1 Gender' }

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我认为我的功能仅适用于第一个实例。我有点不确定如何解决这个问题，并清理所有疯狂的报价等等。

我的目标是将字符串拆分为如下对象：

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mongoExDoc: {
  child1FirstName: "Ali",
  child1Gender: "Female",
  child1HairColor: "Blonde",
  child1HairStyle: "Wavy",
  child1SkinTone: "Tan",
  child2FirstName: "Morgan",
  child2Gender: "Female",
  child2HairColor: "Brown",
  child2HairStyle: "Ponytail",
  child2SkinTone: "Light",
  relationship1To2: "Brother",
  relationship2To1: "Brother"
}

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从那里我将把它的属性与插入到MongoDB中的另一个对象相结合。

非常感谢任何帮助！

Answer 1

如果order.customer.note是您的示例字符串，那么这应该有效：

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let data = "Child 1 First Name: Ali\nChild 1 Gender: Female\nChild 1 Hair Color: Blonde\nChild 1 Hair Style: Wavy\nChild 1 Skin Tone: Tan\nChild 2 First Name: Morgan \nChild 2 Gender: Female\nChild 2 Hair Color: Brown\nChild 2 Hair Style: Ponytail\nChild 2 Skin Tone: Light\nRelationship 1 to 2: Brother\nRelationship 2 to 1: Brother\n";
//let data = JSON.stringify(rawNoteData);  <-- Don't do this. order.customer.note is not an object.

let foo = data.split("\n").reduce(function(obj, str, index) {
  let strParts = str.split(":");
  if (strParts[0] && strParts[1]) { //<-- Make sure the key & value are not undefined
    obj[strParts[0].replace(/\s+/g, '')] = strParts[1].trim(); //<-- Get rid of extra spaces at beginning of value strings
  }
  return obj;
}, {});

console.log(foo);

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Answer 2

我可以想到将字符串转换为对象的两种方法：

创建JSON字符串，并使用JSON#parse解析。

const str = "Child 1 First Name: Ali\nChild 1 Gender: Female\nChild 1 Hair Color: Blonde\nChild 1 Hair Style: Wavy\nChild 1 Skin Tone: Tan\nChild 2 First Name: Morgan \nChild 2 Gender: Female\nChild 2 Hair Color: Brown\nChild 2 Hair Style: Ponytail\nChild 2 Skin Tone: Light\nRelationship 1 to 2: Brother\nRelationship 2 to 1: Brother\n";

const toObject = (str) => {
  const json = str.replace(/([^\:]+)\:([^\n]+)\n/g, (_, p1, p2) => {
    return `"${p1.replace(/\s+/g, '')}":"${p2.trim()}",`;
  });

  return JSON.parse(`{${json.slice(0, -1)}}`);
};


console.log(toObject(str));

或

匹配字符串的部分并迭代以创建对象：

const str = "Child 1 First Name: Ali\nChild 1 Gender: Female\nChild 1 Hair Color: Blonde\nChild 1 Hair Style: Wavy\nChild 1 Skin Tone: Tan\nChild 2 First Name: Morgan \nChild 2 Gender: Female\nChild 2 Hair Color: Brown\nChild 2 Hair Style: Ponytail\nChild 2 Skin Tone: Light\nRelationship 1 to 2: Brother\nRelationship 2 to 1: Brother\n"; const toObject = (str) => { const arr = str.match(/[^\:\n]+/g); const obj = {}; for(let i = 0; i < arr.length; i += 2) { obj[arr[i].replace(/\s+/g, '')] = arr[i + 1].trim(); } return obj; }; console.log(toObject(str));

Answer 3

这样的东西？

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class move : MonoBehaviour {

    public float moveSpeed;

    // Use this for initialization
    void Start () 
    {
        moveSpeed = 10f;
    }

    // Update is called once per frame
    void Update () 
    {
        transform.Translate(moveSpeed*Input.GetAxis("Horizontal")*Time.deltaTime,0f,moveSpeed*Input.GetAxis("Vertical")*Time.deltaTime); 
    }
}

生成一个像你要求的对象

JavaScript将字符串拆分为具有属性的对象

3 个答案: