我正在使用ios 11视觉框架实时生成面部标志点。我能够获得面部标志点并使用面部标志点的UIBezierPath覆盖相机层。但是,我想得到类似右下角的图片。目前我的东西看起来像左图,我尝试循环点并添加中点,但我不知道如何从点生成所有这些三角形。我如何从左边的点开始生成右边的地图?
我不确定我能拿到所有的分数,而不是它会帮助太多,但我也从整个脸部的边界框中得到分数。最后,是否有任何框架可以让我认识到我需要的所有要点,比如openCV或其他什么,请告诉我。谢谢!
以下是我在https://github.com/DroidsOnRoids/VisionFaceDetection中使用的代码:
func detectLandmarks(on image: CIImage) {
try? faceLandmarksDetectionRequest.perform([faceLandmarks], on: image)
if let landmarksResults = faceLandmarks.results as? [VNFaceObservation] {
for observation in landmarksResults {
DispatchQueue.main.async {
if let boundingBox = self.faceLandmarks.inputFaceObservations?.first?.boundingBox {
let faceBoundingBox = boundingBox.scaled(to: self.view.bounds.size)
//different types of landmarks
let faceContour = observation.landmarks?.faceContour
self.convertPointsForFace(faceContour, faceBoundingBox)
let leftEye = observation.landmarks?.leftEye
self.convertPointsForFace(leftEye, faceBoundingBox)
let rightEye = observation.landmarks?.rightEye
self.convertPointsForFace(rightEye, faceBoundingBox)
let leftPupil = observation.landmarks?.leftPupil
self.convertPointsForFace(leftPupil, faceBoundingBox)
let rightPupil = observation.landmarks?.rightPupil
self.convertPointsForFace(rightPupil, faceBoundingBox)
let nose = observation.landmarks?.nose
self.convertPointsForFace(nose, faceBoundingBox)
let lips = observation.landmarks?.innerLips
self.convertPointsForFace(lips, faceBoundingBox)
let leftEyebrow = observation.landmarks?.leftEyebrow
self.convertPointsForFace(leftEyebrow, faceBoundingBox)
let rightEyebrow = observation.landmarks?.rightEyebrow
self.convertPointsForFace(rightEyebrow, faceBoundingBox)
let noseCrest = observation.landmarks?.noseCrest
self.convertPointsForFace(noseCrest, faceBoundingBox)
let outerLips = observation.landmarks?.outerLips
self.convertPointsForFace(outerLips, faceBoundingBox)
}
}
}
}
}
func convertPointsForFace(_ landmark: VNFaceLandmarkRegion2D?, _ boundingBox: CGRect) {
if let points = landmark?.points, let count = landmark?.pointCount {
let convertedPoints = convert(points, with: count)
let faceLandmarkPoints = convertedPoints.map { (point: (x: CGFloat, y: CGFloat)) -> (x: CGFloat, y: CGFloat) in
let pointX = point.x * boundingBox.width + boundingBox.origin.x
let pointY = point.y * boundingBox.height + boundingBox.origin.y
return (x: pointX, y: pointY)
}
DispatchQueue.main.async {
self.draw(points: faceLandmarkPoints)
}
}
}
func draw(points: [(x: CGFloat, y: CGFloat)]) {
let newLayer = CAShapeLayer()
newLayer.strokeColor = UIColor.blue.cgColor
newLayer.lineWidth = 4.0
let path = UIBezierPath()
path.move(to: CGPoint(x: points[0].x, y: points[0].y))
for i in 0..<points.count - 1 {
let point = CGPoint(x: points[i].x, y: points[i].y)
path.addLine(to: point)
path.move(to: point)
}
path.addLine(to: CGPoint(x: points[0].x, y: points[0].y))
newLayer.path = path.cgPath
shapeLayer.addSublayer(newLayer)
}
答案 0 :(得分:5)
我最终找到了一个有效的解决方案。我通过https://github.com/AlexLittlejohn/DelaunaySwift使用了delaunay三角测量,我修改它以使用视觉框架的面部地标检测请求生成的点。使用代码片段无法轻松解释这一点,因此我将下面的github repo链接到了我的解决方案。请注意,这不会从额头获得分数,因为视觉框架只能从眉毛中获得分数。
答案 1 :(得分:0)
右边图片中您想要的是Candide网格。您需要将这些点映射到网格,这将是它。我不认为你需要走上评论中讨论过的路线。
P.S我在浏览着名过滤器应用程序的APK内容时找到了Candide(让我想起了casper) - 还没有时间自己尝试一下。