编辑:这个问题不重复,我不想绘制数字而不是点数,我想在我的点旁边绘制数字。
我正在使用matplotlib创建一个情节。绘制[[3,9],[4,8],[5,4]]
有三点我可以轻松地用它们制作散点图
import matplotlib.pyplot as plt
allPoints = [[3,9],[4,8],[5,4]]
f, diagram = plt.subplots(1)
for i in range(3):
xPoint = allPoints[i][0]
yPoint = allPoints[i][1]
diagram.plot(xPoint, yPoint, 'bo')
产生这个情节:
我想用数字1,2,3标记每个点。
根据this SO回答,我尝试使用注释来标记每个点。
import matplotlib.pyplot as plt
allPoints = [[1,3,9],[2,4,8],[3,5,4]]
f, diagram = plt.subplots(1)
for i in range(3):
pointRefNumber = allPoints[i][0]
xPoint = allPoints[i][1]
yPoint = allPoints[i][2]
diagram.annotate(pointRefNumber, (xPoint, yPoint))
这会产生一个空白图。我正在密切关注另一个答案,但它没有产生任何情节。我在哪里弄错了?
答案 0 :(得分:4)
我解决了自己的问题。我需要绘制点然后注释它们,注释没有内置绘图。
public void playSound(View view){
if (null != mediaPlayer) {
mediaPlayer.stop();
mediaPlayer.release();
}
switch(view.getId())
{
case R.id.button1:
mediaPlayer = MediaPlayer.create(this, R.raw.doyouspeakenglish);
break;
case R.id.button2:
mediaPlayer = MediaPlayer.create(this, R.raw.goodevening);
break;
case R.id.button3:
mediaPlayer = MediaPlayer.create(this, R.raw.hello);
break;
case R.id.button4:
mediaPlayer = MediaPlayer.create(this, R.raw.howareyou);
break;
case R.id.button5:
mediaPlayer = MediaPlayer.create(this, R.raw.ilivein);
break;
case R.id.button6:
mediaPlayer = MediaPlayer.create(this, R.raw.mynameis);
break;
case R.id.button7:
mediaPlayer = MediaPlayer.create(this, R.raw.please);
break;
case R.id.button8:
mediaPlayer = MediaPlayer.create(this, R.raw.welcome);
break;
default:
throw new RuntimeException("Unknown button ID");
}
i++;
Log.i("klik", Integer.toString(i));
mediaPlayer.start();
}
编辑添加fontsize选项,就像在Gregoux的回答
中一样答案 1 :(得分:4)