Question

我有这样的XML。

<language code="eng">
  <label lang="tr">İngilizce</label>
  <label lang="en">English</label>
</language>

这是一个例子。我有402个节点。

我正在尝试使用C＃解析这个XML文件，就像代码一样，我只能得到语言代码值。

这是代码。

var languageCode = doc.Root
                          .Elements("language")
                          .Select(x => new XmlModel
                          {
                              Code = (string) x.Attribute("code"),
                          })
                          .ToList();

但是我需要在相同的代码中获得标签lang =“tr”并标记lang =“en”内部文本（Ingilizce，英语）。我没有这样做。

如何更改我的代码？谢谢你的帮助。：）

编辑：

 var languageCodeAndValue = doc.Root
                  .Elements("language")
                  .SelectMany(x => x.Elements("label").Select(item => new Tuple<string, string>(item.Attribute("lang").Value, item.Value)))
                  .ToList();

这段代码给我一个这样的列表：

tr,Turkce
en,Turkish
tr,Ingilizce
en,English

但我需要

tur,tr,Turkce
tur,en,Turkish
eng,tr,Ingilizce
eng,en,English

Answer 1

If I right understood you, just try this:

var languageCodeAndValue = doc.Root
                      .Elements("language")
                      .SelectMany(x => x.Elements("label").Select(item => new Tuple<string, string, string>(x.Attribute("code").Value, item.Attribute("lang").Value, item.Value)))
                      .ToList();

Your languageCodeAndValue would be contain a language code, it attribute and text: ("eng", "tr", "İngilizce"), ("eng", "en", "English")

And retrive values:

foreach (var value in languageCodeAndValue)
{
    Console.WriteLine(value.Item1);
    Console.WriteLine(value.Item2);
    Console.WriteLine(value.Item3);
}

Answer 2

尝试这样的事情：

$POSTParams = @{
    client_id    = "client-id-value"
    secret       = "secret-value"
    access_token = "access-token-value"
}

Invoke-WebRequest -Uri "https://tartan.plaid.com/balance" -Method POST -Body $POSTParams

Answer 3

解析xml的另一种方法是使用XmlSerializer。如果您将xml复制到剪贴板并选择Past Special＆gt;，Visual Studio可以根据您的xml为您创建类。将XML粘贴为类。然后你可以反序列化xml，你将得到一个language对象，其数组为label s。

void Main()
{
    string xml = @"<language code=""eng"">
      <label lang=""tr"">İngilizce</label>
       <label lang=""en"">English</label>
      </language>";

    XmlSerializer ser = new XmlSerializer(typeof(language));
    using (MemoryStream ms = new MemoryStream())
    {
        XDocument.Parse(xml).Save(ms);
        ms.Position = 0;
        var lang = (language)ser.Deserialize(ms);

        Console.WriteLine(lang.code);
        foreach (languageLabel lbl in lang.label)
        {
            Console.WriteLine(lbl.lang);
            Console.WriteLine(lbl.Value);
        }
    }
}

[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
public partial class language
{

    private languageLabel[] labelField;

    private string codeField;

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute("label")]
    public languageLabel[] label
    {
        get
        {
            return this.labelField;
        }
        set
        {
            this.labelField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public string code
    {
        get
        {
            return this.codeField;
        }
        set
        {
            this.codeField = value;
        }
    }
}

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class languageLabel
{

    private string langField;

    private string valueField;

    /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute()]
    public string lang
    {
        get
        {
            return this.langField;
        }
        set
        {
            this.langField = value;
        }
    }

    /// <remarks/>
    [System.Xml.Serialization.XmlTextAttribute()]
    public string Value
    {
        get
        {
            return this.valueField;
        }
        set
        {
            this.valueField = value;
        }
    }
}

使用C＃从XML中获取值

3 个答案: