Question

我需要一些帮助才能将表格中的数据提取到Json中。我需要查询数据并返回符合WHERE语句的当前年份的所有记录，同时按MONTH对结果进行分组。

我的查询内容是：

$query_Promoter = "
SELECT COUNT(RecordID) AS Score4, FeedBackDate  
FROM ".$FeedBack." 
WHERE FeedBackDate >= DATE_SUB(NOW(),INTERVAL 1 YEAR)
    AND A = 4
    OR B = 4 
    OR C = 4 
    OR D = 4 
    OR E = 4 
    OR F = 4 
    OR G = 4 
    OR H = 4 
    OR L = 4
    OR M = 4 
    OR N = 4 
GROUP BY MONTH(FeedBackDate)";
$Promoter =$conn->query($query_Promoter);
$totalRows_Promoter  = mysqli_num_rows($Promoter);

然后循环结果如：

if($totalRows_Promoter > 0) {
    $rows_Promoter  = array();
    $rows_Promoter ['name'] = 'Promoters';
    while($row_Promoter  = mysqli_fetch_array($Promoter )) {
        $rows_Promoter['Month'][] = date("M", strtotime($row_Promoter['FeedBackDate']));
        $rows_Promoter['data'][] = $row_Promoter['Score4'];
    }
}

$result = array();

if($totalRows_Promoter > 0) {
    array_push($result,$rows_Promoter);
}


print json_encode($result, JSON_NUMERIC_CHECK);

// The resulting JSON is:

[{"name":"Promoters","Month":["Jan","Jan","Jan","Jan"],"data":[3,10,17,1]}]

我想把结果作为：

[{"name":"Promoters","Month":["Jan","Feb","May","Jun"],"data":[3,10,17,1]}]

任何人都可以看到我做错了什么，或者我是以错误的方式接近这个。

非常感谢你的时间。

Answer 1

您可以在SQL语句中完成大部分工作。通过使用GROUP_CONCAT函数和DATE_FORMAT函数，您将最终得到一行，可以轻松地将JSON轻松转换为数组。这是SQL语句：

SELECT 
    'Promoters' as `name`,
    GROUP_CONCAT(DATE_FORMAT(`FeedBackDate`,'%b')) as `Month`,
    GROUP_CONCAT(COUNT(`RecordID`)) AS `data`
FROM $FeedBack
WHERE `FeedBackDate` >= DATE_SUB(NOW(),INTERVAL 1 YEAR)
    AND (A = 4
        OR B = 4 
        OR C = 4 
        OR D = 4 
        OR E = 4 
        OR F = 4 
        OR G = 4 
        OR H = 4 
        OR L = 4
        OR M = 4 
        OR N = 4)
ORDER BY DATE_FORMAT(`FeedBackDate`,'%b')

要从行创建数组，您需要使用GROUP_CONCAT拆分两列，因为它们将是逗号分隔的字符串。

if($totalRows_Promoter > 0) {
    $rows_Promoter  = array();
    $rows_Promoter['name'] = 'Promoters';
    //  Should only have one row in results
    $row_Promoter  = mysqli_fetch_array($Promoter );
    $rows_Promoter['Month'] = explode(',',$row_Promoter['Month']);
    $rows_Promoter['data'] = explode(',',$row_Promoter['data']);
}

$result = json_encode($result, JSON_NUMERIC_CHECK);

echo $result;

查询数据并作为JSON字符串返回

1 个答案: