无法构造java.sql.Time的实例

Question

我正在尝试用邮递员以json格式发布请求。

我的json是：

{
    "bud_year":"123",
    "tran_ndate":"2073-10-10",
    "tran_edate":"17-JUL-14",
    "bank_code":"12an",
    "bank_accno":"123",
    "amount":"12351",
    "payment_name":"1122",
    "voucher_no":"123",
    "depositSlipNo":"123"
}

我的模特课

public class Params {
    private String bud_year;
    private String tran_ndate;

    @JsonFormat(pattern = "yyyy-MM-dd")
    private Time tran_edate;
    private String bank_code;
    private String bank_accno;
    private Long amount;
    private String payment_name;
    private String voucher_no;
    private int depositSlipNo;

    /* getter setters */

}

控制器类

@RequestMapping(value = "/savePayment", method = RequestMethod.POST)
public void savePayment(@RequestBody PaymentParams paymentParams){
 paymentServices.savePayment(paymentParams);
}

错误是：

Could not read JSON document: Can not construct instance of java.sql.Time,
problem: null
Can not construct instance of java.sql.Time, problem: null

17-JUL-14表示2017年7月14日。如何在我的模型类中使tran_edate属性接受17-JUL-14作为时间值？