我是java的新手并试图编写一个程序,将解压缩目录中所有受密码保护的zip文件,我能解压所有正常的zip文件(没有密码)但是我不知道如何解压缩密码受保护的文件 注意:所有zip文件都有相同的密码
import java.io.OutputStream;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.PathMatcher;
import java.nio.file.Paths;
import java.util.List;
import java.util.stream.Stream;
import java.util.zip.ZipEntry;
import net.lingala.zip4j.core.ZipFile;
import net.lingala.zip4j.model.FileHeader;
import java.util.zip.*;
public class Extraction {
// public Extraction() {
//
// try {
//
// ZipFile zipFile = new
// ZipFile("C:\\Users\\Desktop\\ZipFile\\myzip.zip");
//
// if (zipFile.isEncrypted()) {
//
// zipFile.setPassword("CLAIMS!");
// }
//
// List fileHeaderList = zipFile.getFileHeaders();
//
// for (int i = 0; i < fileHeaderList.size(); i++) {
// FileHeader fileHeader = (FileHeader) fileHeaderList.get(i);
//
// zipFile.extractFile(fileHeader, "C:\\Users\\Desktop\\ZipFile");
// System.out.println("Extracted");
// }
//
// } catch (Exception e) {
// System.out.println("Please Try Again");
// }
//
// }
//
// public static void main(String[] args) {
// new Extraction();
//
// }
// }
public static void main(String[] args) {
Extraction unzipper = new Extraction();
unzipper.unzipZipsInDirTo(Paths.get("C:\\Users\\Desktop\\ZipFile"),
Paths.get("C:\\Users\\Desktop\\ZipFile\\Unziped"));
}
public void unzipZipsInDirTo(Path searchDir, Path unzipTo) {
final PathMatcher matcher = searchDir.getFileSystem().getPathMatcher("glob:**/*.zip");
try (final Stream<Path> stream = Files.list(searchDir)) {
stream.filter(matcher::matches).forEach(zipFile -> unzip(zipFile, unzipTo));
} catch (Exception e) {
System.out.println("Something went wrong, Please try again!!");
}
}
public void unzip(Path zipFile, Path outputPath) {
try (ZipInputStream zis = new ZipInputStream(Files.newInputStream(zipFile))) {
ZipEntry entry = zis.getNextEntry();
while (entry != null) {
Path newFilePath = outputPath.resolve(entry.getName());
if (entry.isDirectory()) {
Files.createDirectories(newFilePath);
} else {
if (!Files.exists(newFilePath.getParent())) {
Files.createDirectories(newFilePath.getParent());
}
try (OutputStream bos = Files.newOutputStream(outputPath.resolve(newFilePath))) {
byte[] buffer = new byte[Math.toIntExact(entry.getSize())];
int location;
while ((location = zis.read(buffer)) != -1) {
bos.write(buffer, 0, location);
}
}
}
entry = zis.getNextEntry();
}
} catch (Exception e1) {
System.out.println("Please try again");
}
}
}
答案 0 :(得分:4)
谢谢你们,虽然没有人回答我的问题。 我找到了答案,因为可能有其他人可能正在寻找类似的答案。
import java.io.File;
import java.util.List;
import javax.swing.filechooser.FileNameExtensionFilter;
import net.lingala.zip4j.core.ZipFile;
import net.lingala.zip4j.model.FileHeader;
public class SamExtraction {
public static void main(String[] args) {
final FileNameExtensionFilter extensionFilter = new FileNameExtensionFilter("N/A", "zip");
//Folder where zip file is present
final File file = new File("C:/Users/Desktop/ZipFile");
for (final File child : file.listFiles()) {
try {
ZipFile zipFile = new ZipFile(child);
if (extensionFilter.accept(child)) {
if (zipFile.isEncrypted()) {
//Your ZIP password
zipFile.setPassword("MYPASS!");
}
List fileHeaderList = zipFile.getFileHeaders();
for (int i = 0; i < fileHeaderList.size(); i++) {
FileHeader fileHeader = (FileHeader) fileHeaderList.get(i);
//Path where you want to Extract
zipFile.extractFile(fileHeader, "C:/Users/Desktop/ZipFile");
System.out.println("Extracted");
}
}
} catch (Exception e) {
System.out.println("Please Try Again");
}
}
}
}