Question

从php脚本通过linux bash命令（grep + regex +另一个命令？），我想根据某些条件获取文件的行，见下文：

文件的例子：

"id_line1","value_line1_column2","foo blablabla","value_line1_column4" 
"id_line2","value_line2_column2","blablabla foo","value_line2_column4"
"id_line3","value_line3_column2","blabla foo blabla","value_line3_column4"
"id_line4","value_line4_column2","blablabla","value_line4_column4"
"id_line5","value_line5_column2","fooblabla bla","value_line5_column4"
"id_line6","value_line6_column2","blabla blafoo","value_line6_column4"
"id_line7","value_line7_column2","blabla foobla bla","value_line7_column4"

我只想搜索文件中的列号X（本例中的第三列）。

正则表达式

在我文件的所有行的第三列中，我想查找包含搜索字词的字符串:(通过grep + regex？）

在特定列的字符串的开头（此处为示例，第三列）
OR在特定列的字符串末尾（此处为示例，第三列）
或在特定列的字符串中的某处（此处为示例，第三列）

只找到与其他单词没有连接的单词。例如，使用上面的示例文件，如果我搜索单词“foo”：

"id_line1","value_line1_column2","foo blablabla","value_line1_column4" // the regex must return true
"id_line2","value_line2_column2","blablabla foo","value_line2_column4" // the regex must return true
"id_line3","value_line3_column2","blabla foo blabla","value_line3_column4" // the regex must return true
"id_line4","value_line4_column2","blablabla","value_line4_column4" // the regex must return false
"id_line5","value_line5_column2","fooblabla bla","value_line5_column4" // the regex must return false
"id_line6","value_line6_column2","blabla blafoo","value_line6_column4" // the regex must return false
"id_line7","value_line7_column2","blabla foobla bla","value_line7_column4" // the regex must return false

结果

命令必须返回行：

"id_line1","value_line1_column2","foo blablabla","value_line1_column4"
"id_line2","value_line2_column2","blablabla foo","value_line2_column4"
"id_line3","value_line3_column2","blabla foo blabla","value_line3_column4"

我该怎么做？如果我只能获得id（“id_line1”，“id_line2”，“id_line3”），那将是完美的：）

Answer 1

Awk将完成这项工作：

awk -F, '$3 ~ /"foo / || $3 ~ / foo"/ || $3 ~ /[[:blank:]]foo[[:blank:]]/ { print $0 }' filename

这里我们检查每一行所界定的第三段，并检查＆＃34; foo或（由||表示）一个空格，然后检查foo然后另一个空格，最后是foo＆＃34;。如果发生任何这些情况，请打印

行

在PHP脚本中使用Bash命令，根据特定列的值获取文件的某些行

1 个答案: