我需要在其他列的基础上过滤重复项。这是我正在尝试的代码。不幸的是,它不起作用,因为查询永远不会完成。
Select r1, r2, r3...,rb1,..., rc1,...
From (
Select *, ROW_NUMBER() OVER (PARTITION BY r1 order by r6 DESC) AS rownbr
From
table1
join table2 ON r2=rb1
Join table3 ON r6=rc1
Join table4 ON rx=rdx
) source
Where
rownbr=1
有什么想法吗?
答案 0 :(得分:0)
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假设您的联接是正确的,为什么不使用group by?
Select r1, r2, r3...,rb1,..., rc1,...
From (
Select *
From
table1
join table2 ON r2=rb1
Join table3 ON r6=rc1
Join table 4 ON rx=rdx
) source
group by r1, r2, r3...,rb1,..., rc1,...
答案 1 :(得分:0)
从语法上讲,您似乎已经正确查询了查询。但是,在加入4个没有任何where
子句的表时,您可能会尝试检索太多数据。一些可以改善查询的简单事物将是:
仅指定子查询中需要的列。我很确定你不需要所有4个表中的所有内容。
了解您是否可以更具体地了解您尝试获取的数据并在where
子句中使用它。例如,您可能只是
想要数据,其中t1.createdate> '01 -01-2016'
如果这些仍然无效,您将不得不开始研究索引。
选择r1,r2,r3,rb1
来自(
选择* - 考虑仅指定所需的列。很确定你不需要所有4个表中的每一列。
,ROW_NUMBER()OVER(由r6 DESC按r1顺序划分)AS rownbr
从table1作为t1
将table2连接为t2 ON t1.r2 = t2.rb1
将table3连接为t3 ON t3.r6 = t2.rc1
将table4连接为t4 ON t4.rx = t3.rdx
在哪里 - 可能像约会一样
t1.createdate> '01 -01-2016'
)来源
其中sourece.rownbr = 1
答案 2 :(得分:0)
创建视图的可能解决方案:
CREATE VIEW TABLAEX
AS
select lastname, convert(varchar, birthdate, 103) "birthday",
CONVERT(varchar, hiredate, 103) "hiredate", city,
(DATEDIFF(dd, birthdate, hiredate) + 1)
-(DATEDIFF(wk, birthdate, hiredate) * 2)
-(CASE WHEN DATENAME(dw, birthdate) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, hiredate) = 'Saturday' THEN 1 ELSE 0 END) "working days",
case when city like '%London%' then 'vecino'
when city like '%Seattle%' then 'lejos'
else 'null'
end as val,
case when (DATEDIFF(dd, birthdate, hiredate) + 1)
-(DATEDIFF(wk, birthdate, hiredate) * 2)
-(CASE WHEN DATENAME(dw, birthdate) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, hiredate) = 'Saturday' THEN 1 ELSE 0 END) > 8000 then 'viejo'
else 'joven'
end as edad,
ROW_NUMBER() OVER (PARTITION BY city order by hiredate) AS rownbr
from
HR.Employees;
GO
SELECT DISTINCT lastname, birthday, hiredate, "working days", edad, val
from TABLAEX
WHERE rownbr=1;
GO
DROP VIEW TABLAEX;