情景:
我有一个投票页面,您必须从列表中选择4个候选人中的3个。
需要:
我需要在检查其中的3个(4)后禁用最后一个复选框。
代码:
HTML
<input class="cb" type="checkbox" name="condidate" value="1" onchange="cbChange(this)" />
<input class="cb" type="checkbox" name="condidate" value="2" onchange="cbChange(this)"/>
<input class="cb" type="checkbox" name="condidate" value="3" onchange="cbChange(this)"/>
<input class="cb" type="checkbox" name="condidate" value="4" onchange="cbChange(this)"/>
JS
function cbChange(obj) {
var cbs = document.getElementsByClassName("cb");
for (var i = 0; i < cbs.length - 3; i++) {
cbs[i].disabled = true;
}
obj.disabled = false;
}
问题:
如何在选择其他3个选项后禁用最后一个选项。
答案 0 :(得分:1)
你需要在复选框的点击事件上调用cbChange。
#include <iostream>
#include <cmath>
#include <utility>
#include <cstdlib>
#include <thrust/device_vector.h>
#include <thrust/reduce.h>
#include <thrust/functional.h>
#include <boost/numeric/odeint.hpp>
#include <boost/numeric/odeint/external/thrust/thrust_algebra.hpp>
#include <boost/numeric/odeint/external/thrust/thrust_operations.hpp>
#include <boost/numeric/odeint/external/thrust/thrust_resize.hpp>
using namespace std;
using namespace boost::numeric::odeint;
typedef double value_type;
typedef thrust::device_vector< value_type > state_type;
const value_type n1 = 10.0;
struct Goodwin_system
{
struct Goodwin_functor
{
template< class T >
__host__ __device__
void operator()( T t ) const
{
value_type x1 = thrust::get< 0 >( t );
value_type x2 = thrust::get< 1 >( t );
value_type x3 = thrust::get< 2 >( t );
value_type x4 = thrust::get< 3 >( t );
value_type x5 = thrust::get< 4 >( t );
value_type x6 = thrust::get< 5 >( t );
value_type a = thrust::get< 6 >( t );// For differnt values of a we will get different ODE
thrust::get< 7 >( t ) = a * (77.3*(pow(0.001,n1)/(pow(0.001,n1) + pow(x3,n1))) - x1);
thrust::get< 8 >( t ) = a * (x1-x2);
thrust::get< 9 >( t ) = a * (x2-x3);
thrust::get< 10 >( t ) = a * (x3-x4);
thrust::get< 11 >( t ) = a * (x4-x5);
thrust::get< 12 >( t ) = a * (x5-x6);
}
};
Goodwin_system( size_t N , const state_type &aa ) // aa is for different values of the parameter a
: m_N( N ) , m_aa( aa ) { }
template< class State , class Deriv >
void operator()( const State &x , Deriv &dxdt , value_type t ) const
{
thrust::for_each(
thrust::make_zip_iterator( thrust::make_tuple(
boost::begin( x ) ,
boost::begin( x ) + m_N ,
boost::begin( x ) + 2 * m_N ,
boost::begin( x ) + 3 * m_N ,
boost::begin( x ) + 4 * m_N ,
boost::begin( x ) + 5 * m_N ,
m_aa.begin() ,
boost::begin( dxdt ) ,
boost::begin( dxdt ) + m_N ,
boost::begin( dxdt ) + 2 * m_N,
boost::begin( dxdt ) + 3 * m_N,
boost::begin( dxdt ) + 4 * m_N,
boost::begin( dxdt ) + 5 * m_N ) ) ,
thrust::make_zip_iterator( thrust::make_tuple(
boost::begin( x ) + m_N ,
boost::begin( x ) + 2 * m_N ,
boost::begin( x ) + 3 * m_N ,
boost::begin( x ) + 4 * m_N ,
boost::begin( x ) + 5 * m_N ,
boost::begin( x ) + 6 * m_N ,
m_aa.end() ,
boost::begin( dxdt ) + m_N ,
boost::begin( dxdt ) + 2 * m_N ,
boost::begin( dxdt ) + 3 * m_N,
boost::begin( dxdt ) + 4 * m_N,
boost::begin( dxdt ) + 5 * m_N,
boost::begin( dxdt ) + 6 * m_N)) ,
Goodwin_functor() );
}
size_t m_N;
const state_type &m_aa;
};
size_t N;
void write_ans( const state_type &x , const double t )// For writing the results
{
cout<<t<<"\t";
for( size_t i=0 ; i<6*N ; ++i )
{
cout<<x[i]<<"\t";
}
cout<<endl;
}
const value_type dt = 0.1;
const value_type t_max = 1000.0;
int main( int argc , char* argv[] )
{
N = argc > 1 ? atoi(argv[1]) : 1000;// for 1000 oscillator
vector< value_type > aa_host( N );
const value_type aa_min = value_type(0.01);
for( size_t i=0 ; i<N ; ++i )
aa_host[i] =(i+1)*aa_min;// Generate differnt a values for each iteration
state_type aa = aa_host;
//[ thrust_Goodwin_parameters_integration
state_type x( 6 * N );
// initialize x,y,z
thrust::fill( x.begin() , x.end() , value_type(0.2) );
typedef runge_kutta4< state_type , value_type , state_type , value_type ,
thrust_algebra , thrust_operations > stepper_type;
Goodwin_system Goodwin(N , aa);
integrate_const( stepper_type() , Goodwin , x , value_type(0.1) , t_max , dt, write_ans);
return 0;
}
&#13;
function cbChange(obj) {
var cbs = document.getElementsByClassName("cb");
var checkCount = 0;
for (var i = 0; i < cbs.length; i++) {
if (cbs[i].checked === true)
checkCount++;
cbs[i].disabled = false;
}
if (checkCount >= 3){
for (var i = 0; i < cbs.length; i++) {
if (cbs[i].checked === false)
cbs[i].disabled = true;
}
}
}
&#13;
答案 1 :(得分:1)
当其中一个复选框发生更改时,请计算未选中的数字。如果只有一个,你可以禁用它;否则,如果一个被禁用,则必须重新启用它。