Question

我试图想出一种循环JSON对象并挑选符合特定条件的对象的方法。我需要用结果创建一个新的JSON。我有一个树组件，节点中有复选框。我想只提取被检查的节点。已检查的节点可由"isSelected": true

标识

我是Angular的新手，之前没有处理过JSON循环。任何人都可以帮我解决这个问题吗？

Answer 1

只需使用复选框

上的**

foreign key (dept_name) references department(dept_name)

属性即可

isSelected

<强>样本

   <input type="checkbox" ng-model="listitem.isSelected" >

var app = angular.module('myApp', []);
app.controller('AppCtrl', function($scope, $http) {
$scope.newList =[];
 $scope.list=
    [
  {
    "node": [
      {
        "node": [],
        "pageName": "Upload Files",
        "isSelected": false,
        "node1": [],
        "pagedefinitionId": 7
      },
      {
        "node": [],
        "pageName": "Download Files",
        "isSelected": false,
        "node1": [],
        "pagedefinitionId": 8
      }
    ],
    "pageName": "Manage Files",
    "isSelected": false,
    "node1": [],
    "pagedefinitionId": 4
  },
  {
    "node": [],
    "pageName": "Vendor Request",
    "isSelected": false,
    "node1": [
      {
        "isSelected": false,
        "pageControlId": 89,
        "elementIdentifier": "vendorRequest.add",
        "pageDefinitionId": 355
      },
      {
        "isSelected": false,
        "pageControlId": 90,
        "elementIdentifier": "vendorRequest.submitForApproval",
        "pageDefinitionId": 355
      },
      {
        "isSelected": false,
        "pageControlId": 91,
        "elementIdentifier": "vendorRequest.complete",
        "pageDefinitionId": 355
      }
    ],
    "pagedefinitionId": 355
  }
];
$scope.getselected = function(){
  angular.forEach( $scope.list,function(key,value){
  console.log(key);
      if(key.isSelected){
        $scope.newList.push(key);
      }
  });
}
});

循环访问JSON对象数组并根据条件取出对象

1 个答案: