Rextester

Question

问题：

Input:-gandhi                      output:- Gandhi
Input:-mahatma gandhi              output:- M. Gandhi 
Input:-Mohndas Karamchand ganDhi   output:- M. K. Gandhi

答案：

public class Chef_NITIKA {

    static Scanner scan=new Scanner(System.in);

    public static void main(String[] args) {
        String name=    myString();
        System.out.println("nam is :"+name);
        mySformatter(name);

    }

    private static void mySformatter(String name) {
           int count=0;
          for(char c:name.toCharArray()){
              if(c==' '){
                  count+=1;
              }
          }
          System.out.println(count+" blank spaces");
          if(count==0){
              char ch=name.charAt(0);
              name=Character.toUpperCase(ch)+name.substring(1);
              System.out.println("nam is :"+name);
          }
          else if(count==1){
              char ch=name.charAt(0);
             name= name.replace(' ', '.');
             String subname=name.substring(name.indexOf(".")+1);
             char c=subname.charAt(0);
             subname=Character.toUpperCase(c)+subname.substring(1);
             name=Character.toUpperCase(ch)+"."+subname;
              System.out.println("nam is :"+name);
          }
          else if(count==2){
              char ch=name.charAt(0);
            // name= name.replace(' ', '.');
             String subname=name.substring(name.indexOf(" ")+1);
             System.out.println(subname);
             String subsubname=subname.substring(name.indexOf(" "));
             System.out.println(subsubname);
             char c=subname.charAt(0);
             char c1=subsubname.charAt(0);
             subname=Character.toUpperCase(c)+subname.substring(1);
             name = Character.toUpperCase(ch)+"."+Character.toUpperCase(c)+"."+Character.toUpperCase(c1)+subsubname.substring(1);
              System.out.println("nam is :"+name);
          }
    }

    private static String myString() {
       System.out.println("enter the string");
       String s=scan.nextLine();
       StringBuffer name=new StringBuffer();
     //  name.append(s);
       return s;
    }
}

当我键入＆＃34; abc cde fgh＆＃34;时，我没有得到所需的输出。我得到输出为A.C..fgh

有没有有效的方法来解决这个问题？

不良输出： -

enter the string
iam writing onStack
nam is :iam writing onStack
2 blank spaces
writing onStack
ing onStack
nam is :I.W.Ing onStack

我希望输出为I.W.OnStack

Answer 1

只需将名称拆分为组件，然后形成所需的缩写：

public static String getName(String input) {
    String[] names = input.split("\\s+");
    String output = "";

    // replace 1st through second to last names with capitalized 1st letter
    for (int i=names.length; i > 1; --i) {
        output += names[names.length - i].substring(0, 1).toUpperCase() + ". ";
    }

    // append full last name, first letter capitalized, rest lower case
    output += names[names.length - 1].substring(0, 1).toUpperCase()
           + names[names.length - 1].substring(1).toLowerCase();

    return output;
}

public static void main(String[] args) {
    System.out.println(getName("gandhi"));
    System.out.println(getName("mahatma gandhi"));
    System.out.println(getName("Mohndas Karamchand ganDhi"));
}

<强>输出：

Gandhi
M. Gandhi
M. K. Gandhi

在这里演示：

Rextester

<强>更新

这是link to a demo，我已经更正了原始代码，至少部分是这样。问题是以下几行：

String subsubname = subname.substring(name.indexOf(" "));

我改为：

String subsubname = subname.substring(subname.indexOf(" ") + 1);

您没有正确识别名称第三部分的第一个字符。话虽如此，您目前的方法是冗长，难以阅读和不灵活。在实践中，您可能希望使用更精简的方法解决此问题。

Answer 2

platforms/ios

Answer 3

@Rushabh Oswal you can get desired result by below method

    private static void mySformatter(String name) {
            String [] tempArray=name.split(" ");
            StringBuilder outputStr=new StringBuilder();
            int len=tempArray.length;
            for(int i=0;i<len;i++){
                String str=tempArray[i];
                if (str.isEmpty())
                   continue;

                if(i==len-1)
                outputStr.append(Character.toUpperCase(str.charAt(0))).append(str.substring(1).toLowerCase());
            else
                outputStr.append(Character.toUpperCase(str.charAt(0))).append(". ");

            System.out.println(outputStr.toString());   
        }

字符串子字符串错误

3 个答案:

Rextester