尝试（没有ResultSet）-with-resources语句

Question

This Oracle documentation描述：

  

以下示例使用try-with-resources语句自动关闭java.sql.Statement对象：

jQuery("#bildo_mc_form").submit(function(e){

    console.log("form submitted");

    function callbackFunction(data){
        window.location.href = "http://thanks.com";
        console.log("sucess result" + data.result);
        console.log("sucess msg" + data.msg);
    }

    var url = jQuery(this).prop('action'); // the script where you handle the form input.
    jQuery.ajax({
           type: "GET",
           url: url,
           data: jQuery("#bildo_mc_form").serialize(), // serializes the form's elements.
           dataType: "jsonp",
           contentType: "application/json; charset=utf-8",
           error: function(error){
                // According to jquery docs, this is never called for cross-domain JSONP requests
                console.log("Error Result" + error.result);
            },
           success: callbackFunction
        });

    e.preventDefault(); // avoid to execute the actual submit of the form.
});

该文件未提及try (Statement stmt = con.createStatement()) { ResultSet rs = stmt.executeQuery(query); while (rs.next()) { String coffeeName = rs.getString("COF_NAME"); int supplierID = rs.getInt("SUP_ID"); float price = rs.getFloat("PRICE"); int sales = rs.getInt("SALES"); int total = rs.getInt("TOTAL"); System.out.println(coffeeName + ", " + supplierID + ", " + price + ", " + sales + ", " + total); } } catch (SQLException e) { JDBCTutorialUtilities.printSQLException(e); } 。我知道ResultSet始终没有关闭，导致连接泄漏。我的理解是否正确？