我正在研究一个项目,我试图通过向它们传递相同的变量(回调共享相同的变量)使2个回调相互通信。由于回调函数不能返回值,因此我传递了一个指向主循环(main函数)中赋值的指针。 但是,它根本不起作用!
这是我的代码:
#include <gtk/gtk.h>
static void inc_val (GtkWidget *widget, gpointer data)
{
int* value = data;
*value++;
printf("value is: %d\n", *value);
}
static void inc_val_ten (GtkWidget *widget, gpointer data)
{
int* value = data;
*value+=10;
printf("value is: %d\n", *value);
}
static void activate (GtkApplication *app, gpointer user_data)
{
GtkWidget *window;
GtkWidget *grid;
GtkWidget *button;
int value = 0;
window = gtk_application_window_new (app);
gtk_window_set_title (GTK_WINDOW (window), "Window");
gtk_container_set_border_width (GTK_CONTAINER (window), 10);
grid = gtk_grid_new ();
gtk_container_add (GTK_CONTAINER (window), grid);
button = gtk_button_new_with_label ("Add 1 to value");
g_signal_connect (button, "clicked", G_CALLBACK (inc_val), &value);
gtk_grid_attach (GTK_GRID (grid), button, 0, 0, 1, 1);
button = gtk_button_new_with_label ("Add 10 to value");
g_signal_connect (button, "clicked", G_CALLBACK (inc_val_ten), &value);
gtk_grid_attach (GTK_GRID (grid), button, 1, 0, 1, 1);
button = gtk_button_new_with_label ("Quit");
g_signal_connect_swapped (button, "clicked", G_CALLBACK (gtk_widget_destroy), window);
gtk_grid_attach (GTK_GRID (grid), button, 0, 1, 2, 1);
gtk_widget_show_all (window);
}
int main (int argc, char **argv)
{
GtkApplication *app;
int status;
app = gtk_application_new ("org.gtk.example", G_APPLICATION_FLAGS_NONE);
g_signal_connect (app, "activate", G_CALLBACK (activate), NULL);
status = g_application_run (G_APPLICATION (app), argc, argv);
g_object_unref (app);
return status;
}
该程序在窗口中有3个按钮:
value是主循环上的整数。当按下其中一个按钮(第一个或第二个)时,值变大(按1或10),程序将打印新值。
我已经运行程序并单击按钮,这就是我所拥有的:
value is: 46525384
value is: 46525384
value is: 46157330
value is: -830528646
value is: 56
value is: 10
而不是:
value is: 1
value is: 2
value is: 12
value is: 22
value is: 23
value is: 33
任何人都知道为什么会这样?
感谢您的帮助!
编辑:我尝试了同样的事情,而不是在数字中添加数字,我尝试将按钮添加到网格中。由于答案(在问题下)的解决方案适用于前面的代码,因此我将网格设为全局。
所以这是新代码:
#include <gtk/gtk.h>
#include <stdlib.h>
#include <stdio.h>
GtkWidget *grid;
static void add_button (GtkWidget *widget, gpointer data)
{
static int value = 0;
GtkWidget* grid = data;
value++;
printf("attach to line %d\n", value);
gtk_grid_attach(GTK_GRID(grid), gtk_button_new_from_stock(GTK_STOCK_NEW), 0, value, 1, 1);
}
static void activate (GtkApplication *app, gpointer user_data)
{
GtkWidget *window;
GtkWidget *button;
window = gtk_application_window_new (app);
gtk_window_set_title (GTK_WINDOW (window), "Window");
gtk_container_set_border_width (GTK_CONTAINER (window), 10);
grid = gtk_grid_new ();
gtk_container_add (GTK_CONTAINER (window), grid);
button = gtk_button_new_with_label ("Add Button");
g_signal_connect (button, "clicked", G_CALLBACK (add_button), grid);
gtk_grid_attach (GTK_GRID (grid), button, 0, 0, 1, 1);
gtk_widget_show_all (window);
}
int main (int argc, char **argv)
{
GtkApplication *app;
int status;
app = gtk_application_new ("org.gtk.example", G_APPLICATION_FLAGS_NONE);
g_signal_connect (app, "activate", G_CALLBACK (activate), NULL);
status = g_application_run (G_APPLICATION (app), argc, argv);
g_object_unref (app);
return status;
}
然而,由于某种原因,它无法正常工作。帮助将不胜感激!
答案 0 :(得分:1)
value
位于activate
的本地。当activate
完成时,其局部变量消失了;传递给处理程序的指针现在毫无意义。
解决方案是让value
在应用程序的整个生命周期中幸存。最简单(但可能不是最干净)的方法是使其全球化。
答案 1 :(得分:1)
回答编辑:
您必须显示小部件才能实现它们。最简单的方法是在父容器上调用gtk_widget_show_all
:
static void add_button (GtkWidget *widget, gpointer data)
{
static int value = 0;
GtkWidget* grid = data;
value++;
printf("attach to line %d\n", value);
gtk_grid_attach(GTK_GRID(grid),
gtk_button_new_from_stock(GTK_STOCK_NEW), 0, value, 1, 1);
gtk_widget_show_all(grid);
}
另一种选择是保持对按钮的引用并在该实例上调用gtk_widget_show
。 e.g:
static void add_button (GtkWidget *widget, gpointer data)
{
static int value = 0;
GtkWidget* grid = data;
GtkWidget* button = gtk_button_new_from_stock(GTK_STOCK_NEW);
value++;
printf("attach to line %d\n", value);
gtk_grid_attach(GTK_GRID(grid), button, 0, value, 1, 1);
gtk_widget_show (button);
}