Question

我试图运行一个允许您使用搜索栏的应用程序，它只会返回临时，城市和条件。当我运行它时，我得到一个关于临时值的零回报和一个＆＃39; Code：401 API无效＆＃39;错误。但是，我尝试过的两个代码都应该正常运行。我可能试图从OpenWeather那里获取错误的数据，但我似乎无法找到修复它的地方或方法 - 没有出现其他错误。

我试图结合这个主题的两个教程/指南，但是一个使用不同的API＆amp;另一个是在Swift2中。

谢谢！

import UIKit

class ViewController: UIViewController, UISearchBarDelegate {


    @IBOutlet weak var citySearchBar: UISearchBar!
    @IBOutlet weak var cityLabel: UILabel!
    @IBOutlet weak var conditionLabel: UILabel!
    @IBOutlet weak var tempLabel: UILabel!

    var temp: Int!
    var condition: String!
    var city: String!
    let apiID:String = "d7817e07565a0019c5e7851a59eeca73"

    var exists: Bool = true
    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.

        citySearchBar.delegate = self
    }

    func searchBarSearchButtonClicked(_ searchBar: UISearchBar) {

        let urlRequest = URLRequest(url: URL(string: "http://api.openweathermap.org/data/2.5/weather?q=\(citySearchBar.text!.replacingOccurrences(of: " ", with: "_"))&appid=\(apiID))")!)

        let task = URLSession.shared.dataTask(with: urlRequest) { (data, response, error) in

            if error == nil {
                do {

                    let weatherData = try JSONSerialization.jsonObject(
                        with: data!,
                        options: .mutableContainers) as! [String : AnyObject]

                    let weather = weatherData

                    DispatchQueue.main.async {

                        self.cityLabel.text = self.city
                        self.tempLabel.text = "\((self.temp))°"
                        self.conditionLabel.text = weather.description
                        }

                } catch let jsonError {
                    print(jsonError.localizedDescription)
                }  }  }

        task.resume()
    }  }

Answer 1

首先temp的值是Double而不是Int

var temp = 0.0

其次，您不要在代码中设置temp。 temp的值位于main

中的字典weatherData中

if let main = weatherData["main"] as? [String:Any],
   let tempValue = main["temp"] as? Double {
       self.temp = tempValue
       print(tempValue)
}

Swift3：Openweather API返回nil和API错误

1 个答案: