JS：按嵌套数组中的值分组数组

Question

我有一个数组：

[
  {
    theme: "low battery",
    Number: "S-10",
    components: [ "hardware", "battery" ]
  },
  {
    theme: "bad sync",
    Number: "S-11",
    components: [ "software" ]
  },
  {
    theme: "misc troubles",
    Number: "S-12",
    components: [ "hardware", "software" ]
  }
]

所以我想用＆＃34;组件＆＃34;对这个数组进行分组。值。换句话说，我想知道组件在组件中出现的次数。例如：

[
  {
    component: "hardware",
    amount: 2
  },
  {
    component: "software",
    amount: 2
  },
  {    
    component: "battery",
    amount: 1
  }
]

Answer 1

您可以创建一个地图以有效的方式存储每个组件的数量（查找O（1）的复杂度）：

＆＃13;

＆＃13;

var items = [
  {
    theme: "low battery",
    Number: "S-10",
    components: [ "hardware", "battery" ]
  },
  {
    theme: "bad sync",
    Number: "S-11",
    components: [ "software" ]
  },
  {
    theme: "misc troubles",
    Number: "S-12",
    components: [ "hardware", "software" ]
  }
];

var componentMap = new Map();

items.forEach((item) => {
  item.components.forEach((component) => {
    if (componentMap.has(component)) {
      componentMap.set(component, componentMap.get(component) + 1);
    }
    else {
      componentMap.set(component, 1);
    }
  });
});

var componentCount = [];

componentMap.forEach((value, key) => {
  componentCount.push({
    component: key,
    amount: value
  });
});

console.log(componentCount);

＆＃13;

＆＃13;

＆＃13;

Answer 2

   

 var arr = [
      {
        theme: "low battery",
        Number: "S-10",
        components: [ "hardware", "battery" ]
      },
      {
        theme: "bad sync",
        Number: "S-11",
        components: [ "software" ]
      },
      {
        theme: "misc troubles",
        Number: "S-12",
        components: [ "hardware", "software" ]
      }
    ];
    var components = {};
    arr.forEach(function(val){
        val.components.forEach(function(c){
           components[c] = !(c in components) ? 1 : Number(components[c])+1;
        });
    });

    var componentCount = [];
    for(key in components){
     componentCount.push({'component' : key, 'amount' : components[key]});
    }
    
   console.log(componentCount);

Answer 3

您可以使用forEach()循环和thisArg参数来存储每个组件并增加金额。

var data = [{"theme":"low battery","Number":"S-10","components":["hardware","battery"]},{"theme":"bad sync","Number":"S-11","components":["software"]},{"theme":"misc troubles","Number":"S-12","components":["hardware","software"]}]

var result = []

data.forEach(function(e) {
  var that = this;
  e.components.forEach(function(c) {
    if(!that[c]) {
      that[c] = {component: c, amount: 0}
      result.push(that[c])
    }
    that[c].amount += 1
  })
}, {})

console.log(result)