我有一个非常简单的查询:
TextView textView = (TextView) findViewById(R.id.textView8);
int numberOfColumnsEntered = 0;
public void getNumber(View view) {
// get number logic then
textView.setText("Enter Column No. "+(numberOfColumnsEntered+1)+" in which your letters appear");
}
public void buttondone(View view) {
EditText op = (EditText) findViewById(R.id.operator2);
String num = op.getText().toString();
getlist[numberofColumnsEntered] = Integer.parseInt(num);
numberofColumnsEntered++;
textView.setText("Enter Column No. "+(numberOfColumnsEntered+1)+" in which your letters appear");
if(numberofColumnsEntered == x) {
Toast.makeText(getApplicationContext(), "Inserted", Toast.LENGTH_LONG).show();
}
}
使用constant_score组成了几个(大约10个)其他查询。问题是,在特定条款下,我的查询得分太高,无法取消所有其他查询结果。
以下是解释的一部分:
match: {
field => {
boost: 4,
query: term,
fuzziness: 'AUTO',
}
}
你有没有看到,由于以色列国防军的得分为11.38。 我的其他查询(分数在1到3之间)完全没用。
我的问题是:
如何为查询设置最高可能分数?
或者,更好的是,我可以为查询设置一个分数范围吗?
我想避免对此字段进行constant_score查询,我需要一些TF / IDF并为此字段评分,但不是那么强。
我试过了:
"details" => [
[0] {
"value" => 63.656006,
"description" => "sum of:",
"details" => [
[0] {
"value" => 63.656006,
"description" => "weight(title.de:kandinsky in 1694239) [PerFieldSimilarity], result of:",
"details" => [
[0] {
"value" => 63.656006,
"description" => "score(doc=1694239,freq=1.0 = termFreq=1.0\n), product of:",
"details" => [
[0] {
"value" => 4.0,
"description" => "boost",
"details" => []
},
[1] {
"value" => 11.3820715,
"description" => "idf, computed as log(1 + (docCount - docFreq + 0.5) / (docFreq + 0.5)) from:",
[...]
它更好但在某些情况下它仍然可以获得非常高的分数。
答案 0 :(得分:1)
最后,我在1 - (1/x)
中使用了script_score
函数中的函数分数和脚本分数
GET _search
{
"query": {
"function_score": {
"query": {
"match": {
"postgresql.log.message": "alter"
}
},
"script_score" : {
"script" : {
"params": {
"max_score": 5
},
"source": "params.max_score * (1 - 1 / _score)"
}
}
}
}
}
这样,我的分数将在0到近5之间(max_score)。
您可以使用单词alter
(分数3.9150627)或alter table pgbench_branches add primary key (bid)
(分数4.8539715)来here。
您可以调整1 - (1/x)
函数以更快地接近渐近线。
答案 1 :(得分:0)