Question

MODEL     DateCreated 
----------------------
MODEL_1   2017-07-20
MODEL_1   2017-07-19
MODEL_1   2017-06-10
MODEL_1   2017-06-02
MODEL_2   2017-07-18
MODEL_2   2017-07-17
MODEL_2   2017-06-10
MODEL_2   2017-06-02
MODEL_3   2017-07-20
MODEL_3   2017-07-12
MODEL_3   2017-06-10
MODEL_3   2017-06-02
MODEL_3   2017-05-16

预期结果

DateCreated_Exist_In_All_Model
------------------------------
2017-06-10
2017-06-02

这意味着，只有那些存在于所有模型中的DateCreated才会显示

感谢所有愿意帮助我的人。

Answer 1

一种方法是在创建日期汇总，然后将每个日期出现的不同模型的数量与表格中出现的模型总数进行比较。

SELECT
    DateCreated AS DateCreated_Exist_In_All_Model
FROM [yourTable]
GROUP BY DateCreated
HAVING COUNT(DISTINCT MODEL) = (SELECT COUNT(DISTINCT MODEL) FROM yourTable)

请注意，即使您的数据集中似乎只有3个模型，我们也可以使用子查询使查询更加灵活，该子查询计算整个表中不同模型的数量。

Answer 2

DECLARE @Temp table(Model varchar(1000), DateCreated date)

INSERT INTO @Temp

SELECT  'MODEL_1' , '2017-07-20'

UNION ALL

SELECT 'MODEL_1',   '2017-07-19'

UNION ALL

SELECT 'MODEL_1',   '2017-06-10'

UNION ALL

SELECT 'MODEL_1',   '2017-06-02'

UNION ALL

SELECT 'MODEL_2',   '2017-07-17'

UNION ALL

SELECT 'MODEL_2',   '2017-06-10'

UNION ALL

SELECT 'MODEL_2',   '2017-06-02'

UNION ALL

SELECT 'MODEL_3',   '2017-07-12'

UNION ALL

SELECT 'MODEL_3 ',  '2017-06-10'

UNION ALL

SELECT 'MODEL_3 ',  '2017-06-02'

UNION ALL

SELECT 'MODEL_3' ,  '2017-05-16'


DECLARE @ModelCount int

SELECT @ModelCount = COUNT(distinct Model) from @Temp



SELECT DISTINCT DateCreated FROM  (

SELECT

COUNT(MODEL) OVER(PARTITION BY DateCreated) AS Counts, Model,

DateCreated

FROM @Temp) AS D

WHERE D.Counts = @ModelCount



Or





SELECT DateCreated FROM  (

SELECT

ROW_NUMBER() OVER(PARTITION BY DateCreated ORDER BY DateCreated) as Rownum,

COUNT(MODEL) OVER(PARTITION BY DateCreated) AS Counts, Model,

DateCreated

FROM @Temp) AS D

WHERE D.Counts = @ModelCount and D.Rownum = 1

TSQL - 显示所有Model中存在的日期

2 个答案: