Question

我正在尝试使用codeigniter和node.js为数据库中的推送通知做一个通知表，但是我做了一个数组，其中包含我的会话购物车中的产品ID，但我通过我的函数发送它们看起来像这是错误输出

INSERT INTO storelte_notifications (message,type,product_id,user_id,timestamp) VALUES('low stock', 2, ('4169','4170','4173','4172','4175'), '1', 1499414552)

我怎么能一起发送，但不是因为我发送我想发送我的ID然后将它们与我的通知表一起存储我的代码看起来像这样

通知功能

public function index()
    {
        $this->session->carrito = $this->sale->checar_existe_carrito();
        $array = $this->sale->get_all_cart($this->session->carrito);
        $product_id = array();
        foreach ($array as $key => $value) {
             $product_id[] = $value['id'];
        }
        $this->json($product_id);
        $this->notification->addNotification('low stock', $product_id, $this->session->log['id'], 'low stock',now());
    }

模型

插入通知

public function addNotification($message, $product_id, $user_id, $type = ''){
    $types = array('new' => 0, 'pending' => 1, 'low stock' => 2);
    if (isset($types[$type]) === false) {
        throw new \InvalidArgumentException('Value for third parameter must be one of new, pending, or low stock.');
    }
    $type = $types[$type];
    $timestamp = time();
    $query = "SELECT COUNT(*) AS notificationCount FROM storelte_notifications WHERE product_id IN ? AND type = ? ";
    $previousNotification = $this->db->query($query, array($product_id, $type))->result_array();
    if ($previousNotification[0]['notificationCount'] == 0) {
        $sql = "INSERT INTO storelte_notifications (message,type,product_id,user_id,timestamp) VALUES(?, ?, ?, ?, ?)";
        try {
            if ($this->db->query($sql, array($message, $type, $product_id, $user_id, $timestamp))) {
                return true;
            }else{
                return false;
            }
        } catch (Exception $e) {

        }
    }else{
        return true;
    }
}

Answer 1

也许你可以写这样的SQL：

insert into storelte_notifications (message,type,product_id,user_id,timestamp) 
values ('low stock', 2, '4169', '1', 1499414552),('low stock', 2, '4170', '1', 1499414552)

或者您可以使用foreach

Answer 2

使用foreach循环：

$sql = "INSERT INTO storelte_notifications (message,type,product_id,user_id,timestamp) VALUES(?, ?, ?, ?, ?)";
try {
    foreach ($product_id as $pid) {
        if (!$this->db->query($sql, array($message, $type, $pid, $user_id, $timestamp))) {
            return false;
        }
    }
    return true;
} catch (Exception $e) {

}

当我尝试插入数组ID时，我的代码会发生什么？

2 个答案: