Question

使用Swift 3，该应用程序是一个博客阅读器，使用PHP和JSON从MYSQL数据库读取。

目前我的SearchBar没有按照我想要的方式进行操作，我让它在我的mainArray（第1部分）中使用＆＃39; All＆＃39;范围。在进行过滤时，正在过滤的对象将移至filteredArray。我这样做是因为我无法弄清楚如何让它做我想做的事。

它应该做的是，当用户正在搜索一个对象时，我想让对象显示在mainArray或者followArray中，而不是将它移动到另一个数组，所以它没有结合。基本上过滤tableview并不删除任何部分或组合任何对象，因为它会使用户不知道该对象所在的部分，并且当然要确保范围栏正常工作。

学习如何实施搜索栏，以便在我尝试进一步提升水平时看到我的麻烦。谢谢！

SearchBar＆amp;范围代码

let searchController = UISearchController(searchResultsController: nil)

override func viewDidLoad() {
    // Search Bar
    searchController.searchResultsUpdater = self
    searchController.dimsBackgroundDuringPresentation = false
    definesPresentationContext = true
    myTableView.tableHeaderView = searchController.searchBar
    searchController.searchBar.backgroundColor = UIColor.white
    searchController.searchBar.barTintColor = UIColor.white

    // Scope Bar
    searchController.searchBar.scopeButtonTitles = ["All", "Released", "Unreleased", "Free"]
    searchController.searchBar.delegate = self
}

// Title for Header
func tableView(_ tableView: UITableView, titleForHeaderInSection section: Int) -> String? {

    if !(searchController.isActive && searchController.searchBar.text != "") {

        if section == 0 {
            return "Followed Blogs"
        }
        else {
            return "All Blogs"
        }
    }
    return "Filtered Blogs"
}

// Number of Rows in Section
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {

    if !(searchController.isActive && searchController.searchBar.text != "") {

        if section == 0 {

            return followedArray.count
        }
        else if (section == 1) {

            return mainArray.count
        }
    }
    return filteredArray.count
}

// Number of Sections
func numberOfSections(in tableView: UITableView) -> Int {

    if !(searchController.isActive && searchController.searchBar.text != "") {

        return 2
    }
    return 1
}

// CellForRowAt indexPath
public func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {

    let CellIdentifier = "Cell"
    var cell = tableView.dequeueReusableCell(withIdentifier: CellIdentifier) as! CustomCell

    if cell != cell {
        cell = CustomCell(style: UITableViewCellStyle.default, reuseIdentifier: CellIdentifier)
    }

    // Configuring the cell
    var blogObject: Blog

    if !(searchController.isActive && searchController.searchBar.text != "") {
        if indexPath.section == 0 {
            blogObject = followedArray[indexPath.row] 
            cell.populateCell(blogObject, isFollowed: true, indexPath: indexPath, parentView: self)
        }
        else if indexPath.section == 1 {
            blogObject = mainArray[indexPath.row] 
            cell.populateCell(blogObject, isFollowed: false, indexPath: indexPath, parentView: self)
        }
    }
    else {
        blogObject = filteredArray[indexPath.row] 
        cell.populateCell(blogObject, isFollowed: false, indexPath: indexPath, parentView: self)
    }

    return cell
}

// SEARCH BAR: Filtering Content
func filterContentForSearchText(searchText: String, scope: String = "All") {

    filteredArray = mainArray.filter { Blog in

        let categoryMatch = (scope == "All") || (Blog.blogType == scope)

        return categoryMatch && (Blog.blogName.lowercased().contains(searchText.lowercased()))
    }
    myTableView.reloadData()
}

// SEARCH BAR: Updating Results
func updateSearchResults(for searchController: UISearchController) {

    filterContentForSearchText(searchText: searchController.searchBar.text!)
}

// SEARCH BAR: Scope
func searchBar(_ searchBar: UISearchBar, selectedScopeButtonIndexDidChange selectedScope: Int) {

    filterContentForSearchText(searchText: searchBar.text!, scope: searchBar.scopeButtonTitles![selectedScope])
}

// SEARCH BAR: Updating Scope
func updateSearchResultsForSearchController(searchController: UISearchController) {

    let searchBar = searchController.searchBar
    let scope = searchBar.scopeButtonTitles![searchBar.selectedScopeButtonIndex]
    filterContentForSearchText(searchText: searchController.searchBar.text!, scope: scope)
}

// Deallocating Search Bar
deinit{
    if let superView = searchController.view.superview {
        superView.removeFromSuperview()
    }
}

Answer 1

现在您创建一个数组（filteredArray），并假设您在搜索时有1个部分。

我会删除这个假设。

在filterContentForSearchText方法中，创建一个数组数组（其中每个内部数组代表一个部分）。

然后更新所有表视图数据源方法以使用该数组数组来获取正确的值。

首先，将filteredArray的声明更新为数组数组。

现在更新您的表格视图方法：

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    if !(searchController.isActive && searchController.searchBar.text != "") {
        if section == 0 {
            return followedArray.count
        } else {
            return mainArray.count
        }
    } else {
        return filteredArray[section].count
    }
}

// Number of Sections
func numberOfSections(in tableView: UITableView) -> Int {
    if !(searchController.isActive && searchController.searchBar.text != "") {
        return 2
    } else {
        return filteredArray.count
    }
}

// CellForRowAt indexPath
public func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let CellIdentifier = "Cell"
    var cell = tableView.dequeueReusableCell(withIdentifier: CellIdentifier) as! CustomCell

    if cell != cell {
        cell = CustomCell(style: UITableViewCellStyle.default, reuseIdentifier: CellIdentifier)
    }

    // Configuring the cell
    var blogObject: Blog

    if !(searchController.isActive && searchController.searchBar.text != "") {
        if indexPath.section == 0 {
            blogObject = followedArray[indexPath.row] 
            cell.populateCell(blogObject, isFollowed: true, indexPath: indexPath, parentView: self)
        } else {
            blogObject = mainArray[indexPath.row] 
            cell.populateCell(blogObject, isFollowed: false, indexPath: indexPath, parentView: self)
        }
    } else {
        blogObject = filteredArray[indexPath.section][indexPath.row] 
        cell.populateCell(blogObject, isFollowed: false, indexPath: indexPath, parentView: self)
    }

    return cell
}

最后更新filterContentForSearchText方法：

func filterContentForSearchText(searchText: String, scope: String = "All") {
    let filteredFollowed = followedArray.filter { Blog in
        let categoryMatch = (scope == "All") || (Blog.blogType == scope)

        return categoryMatch && (Blog.blogName.lowercased().contains(searchText.lowercased()))
    }

    let filteredMain = mainArray.filter { Blog in
        let categoryMatch = (scope == "All") || (Blog.blogType == scope)

        return categoryMatch && (Blog.blogName.lowercased().contains(searchText.lowercased()))
    }

    filteredArray = [ filteredFollowed, filteredMain ]

    myTableView.reloadData()
}

Swift：让SearchBar搜索两个部分，而不是将它们组合起来

1 个答案: