将数据从一张纸移动到另一张 - GoogleSheet

时间:2017-07-06 21:42:27

标签: google-apps-script

我试图根据触发词" order"将一行数据从一个工作表(IT库存)移动到另一个工作表(InventoryAllocation)。在“操作”列中。当数字变为0时,Action列变为ORDER ...这有效:

IT Inventory

但我也想让整行移到第二张(InventoryAllocation)并从第一张纸上删除它。

InventoryAllocation

我的问题是我应该在脚本中更改哪些变量/声明,因为我尝试了各种变量/声明并继续收到错误:

TypeError:无法读取属性" source"来自undefined。 (第6行,文件"代码")

这是我正在使用的脚本:

/**
 * Moves row of data to another spreadsheet based on criteria in column 5 to sheet with same name as the value in column 6.
*/

function onEdit(e) {
  var ss = e.source;
  var s = ss.getActiveSheet();
  var r = e.range;

  // The code below logs the ID for the active spreadsheet.
 Logger.log(SpreadsheetApp.getActiveSpreadsheet().getId());

  // to let you modify where the action and move columns are in the form responses sheet
  var actionCol = 5;
  var nameCol = 6;

  // Get the row and column of the active cell.
  var rowIndex = r.getRowIndex();
  var colIndex = r.getColumnIndex();

  // Get the number of columns in the active sheet.
  // -1 to drop our action/status column
  var colNumber = s.getLastColumn()-1;

  // if the action/status col is changed to ok do stuff. Change "ok" below to whatever you want the trigger word to be.
  if (e.value == "ORDER" && colIndex == actionCol) {
    // get our target sheet name - in this example we are using the Skin Type column
    var targetSheet = s.getRange(rowIndex, nameCol).getValue();
    // if the sheet exists do more stuff
    if (ss.getSheetByName(targetSheet)) { 
      // set our target sheet and target range
      var targetSheet = ss.getSheetByName(targetSheet);
      var targetRange = targetSheet.getRange(targetSheet.getLastRow()+1, 1, 1, colNumber);
      // get our source range/row
      var sourceRange = s.getRange(rowIndex, 1, 1, colNumber);
      // new sheets says: 'Cannot cut from form data. Use copy instead.' 
      sourceRange.copyTo(targetRange);
      // ..but we can still delete the row after.  Put // in front of below row if you don't want to delete after copying to new sheet
      s.deleteRow(rowIndex);
      // or remove // below if you want to keep but note the move, but you'll need to add // to row above if removing // from below
      //  r.setValue("Copied");
    }
  }
}

非常感谢任何帮助。

谢谢!

0 个答案:

没有答案