我试图弄清楚如何根据比较过滤对象。
我得到一个看起来像这样的对象,虽然有15个结果......
stdClass Object
(
[FlightInfoExResult] => stdClass Object
(
[next_offset] => 15
[flights] => Array
(
[0] => stdClass Object
(
[faFlightID] => SWA2078-1499232401-airline-0885
[ident] => SWA2078
[aircrafttype] => B738
[filed_ete] => 03:00:00
[filed_time] => 1499232401
[filed_departuretime] => 1499477700
[filed_airspeed_kts] => 423
[filed_airspeed_mach] =>
[filed_altitude] => 0
[route] =>
[actualdeparturetime] => 0
[estimatedarrivaltime] => 1499489100
[actualarrivaltime] => 0
[diverted] =>
[origin] => KPHX
[destination] => KMKE
[originName] => Phoenix Sky Harbor Intl
[originCity] => Phoenix, AZ
[destinationName] => General Mitchell Intl
我需要过滤此对象,因此只返回[flights]
[filed_departuretime]
,$time = strtotime($item['departure_time']);
位于查询结果{1}}
做这样的事情:
abs($object->filed_departuretime - $time) <= 3600)
希望这一切都有意义,感谢您的帮助:)我真的不知道array_filter是如何工作的所以这就是我到目前为止所拥有的......
//set flight identity
$ident = $item['airline'].$item['flight_number'];
$date = date('Y-m-d H:i:s');
$time = strtotime($item['departure_time']);
//get flightaware results
$flightAwareResult = FlightInfoEx($ident);
/*$flightResult = array_filter(
$flightAwareResult,
);*/
答案 0 :(得分:0)
数组过滤器接受一个数组并通过函数传递每个元素。它只保留函数返回true值的元素。例如:
//set flight identity
$ident = $item['airline'].$item['flight_number'];
$date = date('Y-m-d H:i:s');
$time = strtotime($item['departure_time']);
//get flightaware results
$flightAwareResult = FlightInfoEx($ident);
$filtered_array = array_filter($flightAwareResult->FlightInfoExResult->flights, function ($value) use ($time) {
return $time - $value->filed_departuretime) <= 3600;
});
答案 1 :(得分:0)
试试这个
$object='';
$object=json_decode(json_encode($object,true),true);
$result=array_map(function ($array){
$time = strtotime($array['departure_time']);
if(($array['filed_departuretime'] - $time) <= 3600){
return $array;
}
},$object['FlightInfoExResult']['flights']);
$result=array_filter($result);
代替$object
放置您的对象变量名称。
我会帮助你。