Question

更新：有人错误地编辑了我的问题，但现在已修复

假设我有以下关联数组：

Array ( 
[Postponement no issue for Man Utd (BBC) ] => 8 
[Postponement no issue for Man Utd ] => 7 
[Postponement no issue for Man Utd: Manchester United say they have no issue over Sunday's game at Chelsea being ... ] => 3
)

你会注意到所有三个键都出现了“Man Utd的推迟没有问题”这个词。我想把这个数组变成一个像这样的新数组：

Array ( [Postponement no issue for Man Utd] => 18 )

其中18是所有值的总和，其中键包含“Man Utd的延期无问题”。

换句话说：如果一个键出现在另一个键中，后者将从新数组中删除，并将其值添加到前一个键的值上。

这可能吗？怎么样？提前谢谢。

Answer 1

foreach($array as $k1 => $v1)
        foreach($array as $k2 => $v2)
             if(strpos($k2, $k1) !== false) // or === 0
                   $result[$k1] = (isset($result[$k1]) ? $result[$k1] : 0) + $v2;

未测试

Answer 2

一个简单的方法可能是：

$original_array = array(...); // The original array with keys and values
asort($original_array); // Sort the array by its keys
$clean_array = array();
foreach ($original_array as $key => $value)
{
  foreach (array_keys($clean_array) as $clean_key)
  {
    $found = false;

    if (preg_match('/'.preg_quote($clean_key).'/', $key))
    {
      $clean_array[$clean_key] += $value;
      $found = true;

      break;
    }

    if (!$found) $clean_array[$key] = $value;
  }
}

Answer 3

好的......这样做的唯一方法是迭代数组两次，并有一个比较它们的函数：

foreach ($my_array as $key1 => $value1) {
    foreach ($my_array as $key2 => $value2) {
        if ($key1 != $key2) { // don't compare them if they're the same
            if (compareKeys($key1,$key2)) {
                $my_array[$key1] += $value2;
                unset($my_array[$key2]);
            }
        }
    }
}

然后你的compareKeys函数看起来像这样：

function compareKeys($val1,$val2) {
    return (strpos($val1,$val2)!==false);
}

Answer 4

根据您的数据大小，这可能不可行。几乎肯定有一个更优化的解决方案，但这有效：

<?php
$array = array(
    'Postponement no issue for Man Utd (BBC)' => 8, 
    'Postponement no issue for Man Utd' => 7,
    'Postponement no issue for Man Utd: Manchester United say they have no issue over Sunday\'s game at Chelsea being ...' => 3
);

$keys = array_keys($array);
usort($keys, 'lengthCmp');
$flippedKeys = array_flip($keys);

$data = array();

foreach ($keys as $k => $v)
{
 $sum = 0;

 foreach ($array as $key => $val)
 {
  if (stripos($key, $v) !== FALSE)
  {
   $sum += $val;
   unset($array[$key]);
   unset($keys[$flippedKeys[$v]]);
  }
 }

 $data[$v] = $sum;
}

foreach ($data as $key => $val)
{
 if ($val == 0)
  unset($data[$key]);
}

var_dump($data);

function lengthCmp($a, $b)
{
 return strlen($a) - strlen($b);
}
?>

输出：

array(1) {["Postponement no issue for Man Utd"] => int(18)}

使用此数据集：

$array = array(
    'test test' => 1,
    'Postponement no issue for Man Utd (BBC)' => 8, 
    'Postponement no issue for Man Utd' => 7,
    'Postponement no issue for Man Utd: Manchester United say they have no issue over Sunday\'s game at Chelsea being ...' => 3,
    'test' => 1,
    'not here' => 1,
    'another test' => 1
);

输出：

array(3) {
    ["test"] => int(3)
    ["not here"] => int(1)
    ["Postponement no issue for Man Utd"] => int(18)
}

php - 如何从关联数组中清除类似项？

4 个答案: