Question

我正在尝试为Mozilla Firefox创建一个插件。我为浏览器操作工具栏图标创建了一个弹出窗口。现在我只想点击弹出窗口中的按钮发出AJAX请求。我怎么能这样做？

我尝试了一些东西。

我的popup.html

<!DOCTYPE html>
<html>
<body>

<div id="demo">
<h2>The XMLHttpRequest Object</h2>
<button type="button" onclick="loadDoc()">Change Content</button>
</div>

<script>
function loadDoc() {
  var xhttp = new XMLHttpRequest();
  xhttp.onreadystatechange = function() {
    if (this.readyState == 4 && this.status == 200) {
      document.getElementById("demo").innerHTML =
      this.responseText;
    }
  };
  xhttp.open("GET", "http://localhost/bestOfDeals", true);
  xhttp.send();
}
</script>

</body>
</html>

AJAX请求返回一些JSON数据但这不起作用。我做错了什么？

还添加了我的浏览器动作弹出窗口的截图。

的manifest.json

{
  "description": "description",
  "manifest_version": 2,
  "name": "Assistant",
  "version": "1.0",
  "homepage_url": "https://www.xxxxxxxx.com/",
  "icons": {
    "48": "icons/logo.png"
  },
  "background": {
    "scripts": ["background.js"]
  },

  "permissions": [
    "tabs",
    "activeTab",
    "notifications",
    "desktop-notification": {
      "description": "Needed for creating system notifications."
    }
  ],  

  "browser_action": {
    "default_icon": "icons/logo.png",
    "default_title": "Assistant",
    "default_popup": "popup/popup_menu.html"
  },

  "content_scripts": [
    {
      "matches": ["*://*/"],
      "js": ["content_scripts/content-script.js"]
    }
  ]
}

来自Firefox浏览器操作的JavaScript Ajax请求弹出

0 个答案: