PHP：MY​​SQLI按样式更改顺序

Question

嗨，我想从chat表中获取数据：

6
7
8

我的代码显示如下：

8
7
6

代码：

"SELECT * FROM `chat` WHERE 
    `chat-code` = 'vm1mxo3dpi9gzuo' AND (`user_1` = '1' OR `user_2` = '1') 
     ORDER BY id DESC LIMIT 3"

Answer 1

{{1}}

尝试以上查询。

Answer 2

因为您按降序排序结果。您应该删除ORDER BY中的 desc 。您可以明确地将ASC指示为升序。

Answer 3

您只需将查询更改为此（按文字ASC排序）：

SELECT * FROM `chat`
WHERE `chat-code` = 'vm1mxo3dpi9gzuo' AND
(`user_1` = '1' OR `user_2` = '1')
ORDER BY text ASC LIMIT 3

如果您仍想按ID订购，只需将DESC更改为ASC

即可

Answer 4

尝试阅读使用DESC或ASC语句时会发生什么。 https://dev.mysql.com/doc/refman/5.7/en/sorting-rows.html 希望它会对你有所帮助。

Answer 5

使用此垫子，如果不起作用，您可以使用准备好的statements.comment更改介于参数之间。

"SELECT * FROM `chat` WHERE `chat-code` = 'vm1mxo3dpi9gzuo'
AND (`user_1`='1' OR `user_2` = '1') 
AND `id` between 6 and 10  //starting and ending offset for query so query doesn't take long time
ORDER BY id ASC LIMIT 3" // LIMIT 3 as you mentioned and ASC order 

Answer 6

我有你的问题的解决方案 - 使用以下查询：

SELECT * FROM (
    SELECT * FROM `chat`
    WHERE `chat-code` = 'vm1mxo3dpi9gzuo' AND
    (`user_1` = '1' OR `user_2` = '1')
    ORDER BY `text` DESC LIMIT 3
) t ORDER BY `text` ASC

Answer 7

SELECT a.*
  FROM 
     ( SELECT * 
         FROM chat 
        WHERE `chat-code` = 'vm1mxo3dpi9gzuo' 
          AND 1 IN(user_1,user_2) 
        ORDER 
           BY id DESC 
        LIMIT 3
     ) a
 ORDER 
    BY id;