Question

注意：使用DISTINCT无法解决问题。（我会解释原因）

这是我的代码

DROP TABLE tmdb_movies;
CREATE TABLE tmdb_movies (
  tmdb_id INTEGER NOT NULL PRIMARY KEY,
  movie_title TEXT NOT NULL
);

INSERT INTO tmdb_movies (tmdb_id, movie_title) VALUES
(1, 'The Dark Knight');

DROP TABLE recommendations;
CREATE TABLE recommendations (
  recommendations_tmdb_id INTEGER NOT NULL,
  recommendations_title TEXT NOT NULL,
  recommendations_vote_average TEXT NOT NULL
);




INSERT INTO recommendations (recommendations_tmdb_id, recommendations_title, recommendations_vote_average) VALUES
(1, 'The Dark Knight Rises', '7.5'),
(1, 'Batman Begins', '7.5'),
(1, 'Iron Man', '7.3'),
(1, 'The Lord of the Rings: The Return of the King', '8.1'),
(1, 'The Lord of the Rings: The The Fellowship of the Ring', '8'),
(1, 'The Lord of the Rings: The Two Towers', '7.9'),
(1, 'The Matrix', '7.9'),
(1, 'Inception', '8'),
(1, 'Iron Man 2', '6.6'),
(1, 'Captain America: The First Avenger', '6.6');

DROP TABLE cast;
CREATE TABLE cast (
  cast_tmdb_id INTEGER NOT NULL,
  cast_name TEXT NOT NULL,
  cast_character TEXT NOT NULL
);

INSERT INTO cast (cast_tmdb_id, cast_name, cast_character) VALUES
(1, 'Christian Bale', 'Bruce Wayne / Batman'),
(1, 'Michael Caine', 'Alfred Pennyworth'),
(1, 'Heath Ledger', 'The Joker'),
(1, 'Aaron Eckhart', 'Harvey Dent / Two-Face'),
(1, 'Gary Oldman', 'Lt. James Gordon'),
(1, 'Maggie Gyllenhaal', 'Rachel Dawes'),
(1, 'Morgan Freeman', 'Lucius Fox'),
(1, 'Chin Han', 'Lau'),
(1, 'Eric Roberts', 'Salvatore Maroni'),
(1, 'Monique Gabriela Curnen', 'Ramirez');



SELECT tmdb_movies.movie_title
,GROUP_CONCAT(recommendations.recommendations_title) as recommendations_title
,GROUP_CONCAT(recommendations.recommendations_vote_average) as recommendations_vote_average

FROM tmdb_movies  

LEFT JOIN cast ON cast.cast_tmdb_id=tmdb_movies.tmdb_id
LEFT JOIN recommendations ON recommendations.recommendations_tmdb_id=tmdb_movies.tmdb_id

Where tmdb_movies.tmdb_id= 1

GROUP BY tmdb_movies.movie_title

Complete SQL Fiddle

如您所见，来自recommendations表的记录多次显示。但如果我删除此行LEFT JOIN cast ON cast.cast_tmdb_id=tmdb_movies.tmdb_id 然后，它们不会多次显示。所以这一行是主要问题。

我的SQL查询中没有使用强制转换表，只是为了简单起见。但我需要它。

是的，我需要group_concat在我的PHP代码中一起显示记录

为什么DISTINCT无法解决问题？好吧，有些电影的评分相同，例如：7.5。因此，并非所有电影的评级都会显示出来。这就是为什么，你可以自己尝试，尝试在小提琴中使用

QL

Answer 1

你觉得这个结果好吗？

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group_concat在SQL Query

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