我有一个按帐户键排序的数据集。当来到某些具有NULL作为组密钥的行时，它应该将当前帐户密钥添加为所有上述行的父键，这些行具有NULL作为父键。因此，当使用null作为组键来到下一行时，您可以将当前帐户密钥设置为上面具有父键（如null）的所有行的父键。
我曾尝试将下面的数据集复制为标记下表，但正如您所见，我不能说我成功得很好，但我希望你们中的一些人可以帮助使用t-sql语法来创建父子层次结构这个
| AccountKey | ParentKey | GroupKey | AccountNumber | Cat | LineName | LineId |
|------------|-----------|----------|---------------|----------|------------------------------|--------------------------------------|
| 1 | NULL | 7 | 3040 | Account | Salg fisk | C6BCDFB2-1AAC-4D05-94F1-879CDC615D76 |
| 2 | NULL | 7 | 3041 | Account | Salg fisk | C6BCDFB2-1AAC-4D05-94F1-879CDC615D76 |
| 3 | NULL | 7 | 3081 | Account | Salg fisk | C6BCDFB2-1AAC-4D05-94F1-879CDC615D76 |
| 4 | NULL | 7 | 3082 | Account | Salg fisk | C6BCDFB2-1AAC-4D05-94F1-879CDC615D76 |
| 5 | NULL | 7 | 3083 | Account | Salg fisk | C6BCDFB2-1AAC-4D05-94F1-879CDC615D76 |
| 6 | NULL | 7 | 3085 | Account | Salg fisk | C6BCDFB2-1AAC-4D05-94F1-879CDC615D76 |
| 7 | NULL | 7 | 3086 | Account | Salg fisk | C6BCDFB2-1AAC-4D05-94F1-879CDC615D76 |
| 8 | NULL | 7 | 3087 | Account | Salg fisk | C6BCDFB2-1AAC-4D05-94F1-879CDC615D76 |
| 9 | NULL | 2 | 3000 | Account | Salg annet | 26AC86B2-0667-463E-B994-11A5C6D519A6 |
| 10 | NULL | 2 | 3010 | Account | Salg annet | 26AC86B2-0667-463E-B994-11A5C6D519A6 |
| 11 | NULL | 2 | 3020 | Account | Salg annet | 26AC86B2-0667-463E-B994-11A5C6D519A6 |
| 12 | NULL | 2 | 3030 | Account | Salg annet | 26AC86B2-0667-463E-B994-11A5C6D519A6 |
| 41 | NULL | 11 | 3050 | Account | Andre driftsinntekter | 65FFB620-AE42-4BE5-A6E7-BF3339AA04DF |
| 42 | NULL | 11 | 3600 | Account | Andre driftsinntekter | 65FFB620-AE42-4BE5-A6E7-BF3339AA04DF |
| 43 | NULL | 11 | 3601 | Account | Andre driftsinntekter | 65FFB620-AE42-4BE5-A6E7-BF3339AA04DF |
| 44 | NULL | 11 | 3610 | Account | Andre driftsinntekter | 65FFB620-AE42-4BE5-A6E7-BF3339AA04DF |
| 45 | NULL | 11 | 3615 | Account | Andre driftsinntekter | 65FFB620-AE42-4BE5-A6E7-BF3339AA04DF |
| 46 | NULL | 11 | 3690 | Account | Andre driftsinntekter | 65FFB620-AE42-4BE5-A6E7-BF3339AA04DF |
| 47 | NULL | 11 | 3691 | Account | Andre driftsinntekter | 65FFB620-AE42-4BE5-A6E7-BF3339AA04DF |
| 48 | NULL | 11 | 3701 | Account | Andre driftsinntekter | 65FFB620-AE42-4BE5-A6E7-BF3339AA04DF |
| 49 | NULL | 11 | 3705 | Account | Andre driftsinntekter | 65FFB620-AE42-4BE5-A6E7-BF3339AA04DF |
| 50 | NULL | 11 | 3720 | Account | Andre driftsinntekter | 65FFB620-AE42-4BE5-A6E7-BF3339AA04DF |
| 67 | NULL | NULL | NULL | SubTotal | Sum inntekter | NULL |
| 68 | NULL | 13 | 4120 | Account | Innkjøp smolt/settefisk/rogn | F9EE1CE4-22C7-400B-BC9D-E2D3214A5113 |
| 69 | NULL | 10 | 4010 | Account | Vareforbruk fôr | 04E63B6D-CA54-423D-8A44-A4ED99861975 |
| 70 | NULL | 10 | 4901 | Account | Vareforbruk fôr | 04E63B6D-CA54-423D-8A44-A4ED99861975 |
| 71 | NULL | 3 | 4000 | Account | Andre varekostnader | DB7FABAB-7ABA-4B9A-9720-1B538D99B3C8 |
| 72 | NULL | 3 | 4020 | Account | Andre varekostnader | DB7FABAB-7ABA-4B9A-9720-1B538D99B3C8 |
| 73 | NULL | 3 | 4030 | Account | Andre varekostnader | DB7FABAB-7ABA-4B9A-9720-1B538D99B3C8 |
| 133 | NULL | 8 | 4925 | Account | Beholdningsendring fisk | A8BA6F19-A792-44A1-AA21-8F79DB24D224 |
| 134 | NULL | NULL | NULL | SubTotal | Sum varekostnader | NULL |
| 135 | NULL | 12 | 5000 | Account | Lønn og sosiale kostnader | 5C475EDE-3731-4D39-B11A-C8EE72213FF6 |
| 136 | NULL | 12 | 5001 | Account | Lønn og sosiale kostnader | 5C475EDE-3731-4D39-B11A-C8EE72213FF6 |
| 137 | NULL | 12 | 5005 | Account | Lønn og sosiale kostnader | 5C475EDE-3731-4D39-B11A-C8EE72213FF6 |
| 138 | NULL | 12 | 5009 | Account | Lønn og sosiale kostnader | 5C475EDE-3731-4D39-B11A-C8EE72213FF6 |
| 263 | NULL | NULL | NULL | SubTotal | Sum lønnskostnadern | NULL |
| 462 | NULL | NULL | NULL | SubTotal | RESULTAT ETTER SKATT | NULL
答案 0 :(得分：2)
如果我理解你的问题，你可以使用：
SELECT Accountkey, ParentKey,GroupKey,AccountNumber, NEW_PARID
FROM (
SELECT Accountkey, ParentKey,GroupKey,AccountNumber, AccountKey AS NEW_PARID, LAG(ACCOUNTKEY) OVER (ORDER BY Accountkey) AS PREC
FROM MYT
WHERE GroupKey IS NULL
UNION ALL
SELECT A.Accountkey, A.ParentKey,A.GroupKey,A.AccountNumber, B.Accountkey AS NEW_PARID, B.PREC
FROM MYT A
INNER JOIN ( SELECT Accountkey, ParentKey,GroupKey,AccountNumber, AccountKey AS NEW_PARID, LAG(ACCOUNTKEY) OVER (ORDER BY Accountkey) AS PREC
FROM MYT
WHERE GroupKey IS NULL) B ON A.Accountkey < B.Accountkey AND (B.PREC IS NULL OR B.PREC<A.accountKey)
WHERE A.GroupKey IS NOT NULL
AND B.GroupKey IS NULL
) X ORDER BY ACCOUNTKEY
您也可以用这种方式编写它（它是相同的查询）：
WITH X AS (SELECT Accountkey, ParentKey,GroupKey,AccountNumber, AccountKey AS NEW_PARID, LAG(ACCOUNTKEY) OVER (ORDER BY Accountkey) AS PREC
FROM MYT
WHERE GroupKey IS NULL)
SELECT X.*
FROM X
UNION ALL
SELECT A.Accountkey, A.ParentKey,A.GroupKey,A.AccountNumber, X.Accountkey AS NEW_PARID, X.PREC
FROM MYT A
INNER JOIN X ON A.Accountkey < X.Accountkey AND (X.PREC IS NULL OR X.PREC<A.accountKey)
WHERE A.GroupKey IS NOT NULL
输出（MYT是表的名称，新的parentid列是NEW_PARID）：
+------------+-----------+----------+---------------+-----------+
| Accountkey | ParentKey | GroupKey | AccountNumber | NEW_PARID |
+------------+-----------+----------+---------------+-----------+
| 1 | NULL | 7 | 3040 | 67 |
| 2 | NULL | 7 | 3041 | 67 |
| 3 | NULL | 7 | 3081 | 67 |
| 4 | NULL | 7 | 3082 | 67 |
| 5 | NULL | 7 | 3083 | 67 |
| 6 | NULL | 7 | 3085 | 67 |
| 7 | NULL | 7 | 3086 | 67 |
| 8 | NULL | 7 | 3087 | 67 |
| 9 | NULL | 2 | 3000 | 67 |
| 10 | NULL | 2 | 3010 | 67 |
| 11 | NULL | 2 | 3020 | 67 |
| 12 | NULL | 2 | 3030 | 67 |
| 41 | NULL | 11 | 3050 | 67 |
| 42 | NULL | 11 | 3600 | 67 |
| 43 | NULL | 11 | 3601 | 67 |
| 44 | NULL | 11 | 3610 | 67 |
| 45 | NULL | 11 | 3615 | 67 |
| 46 | NULL | 11 | 3690 | 67 |
| 47 | NULL | 11 | 3691 | 67 |
| 48 | NULL | 11 | 3701 | 67 |
| 49 | NULL | 11 | 3705 | 67 |
| 50 | NULL | 11 | 3720 | 67 |
| 67 | NULL | NULL | NULL | 67 |
| 68 | NULL | 13 | 4120 | 134 |
| 69 | NULL | 10 | 4010 | 134 |
| 70 | NULL | 10 | 4901 | 134 |
| 71 | NULL | 3 | 4000 | 134 |
| 72 | NULL | 3 | 4020 | 134 |
| 73 | NULL | 3 | 4030 | 134 |
| 133 | NULL | 8 | 4925 | 134 |
| 134 | NULL | NULL | NULL | 134 |
| 135 | NULL | 12 | 5000 | 263 |
| 136 | NULL | 12 | 5001 | 263 |
| 137 | NULL | 12 | 5005 | 263 |
| 138 | NULL | 12 | 5009 | 263 |
| 263 | NULL | NULL | NULL | 263 |
| 462 | NULL | NULL | NULL | 462 |
+------------+-----------+----------+---------------+-----------+
更新20171221 - 适用于MSSQL 2008 您可以尝试这样做（但如果您有大型数据集，请注意性能）：
SELECT A.ACCOUNTKEY
, A.PARENTKEY
, (SELECT MIN(B.ACCOUNTKEY) FROM MYT B WHERE B.GROUPKEY IS NULL AND A.ACCOUNTKEY<=B.ACCOUNTKEY) AS NEW_PARID
FROM MYT A
/* WHERE A.GROUPKEY IS NOT NULL*/
答案 1 :(得分：0)
这是我需要重写以处理SQL Server 2008的代码
$("#load-html").click(function() {
window.location.href = 'http://yourdomain.com/new-html'
})