Question

我有3张桌子。 Cable，PhysicalPoint和Interconnect。

Cable包含两个PhysicalPoint（上坡，下坡）和Interconnect包含一个PhysicalPoint。我想要求Cable与PhysicalPoint共有Interconnect的所有#cable, physicalpoint and interconnect are sqlalchemy.Table c = cable.alias('c') pdh = physicalpoint.alias('pdh') puh = physicalpoint.alias('puh') idh = interconnect.alias('idh') iuh = interconnect.alias('iuh') j = c.outerjoin(pdh, pdh.c.id==c.c.cab_downhill)\ .outerjoin(puh, puh.c.id==c.c.cab_uphill) # this is where I don't know what to do... j2 = outerjoin(idh, pdh, pdh.c.id==idh.c.id) j3 = outerjoin(iuh, puh, puh.c.id==iuh.c.id) # this works but how to integrate the two other join ? db.execute(select(c.c).select_from(j))。我认为它与SQL有关，但不是sqlalchemy。

SELECT c.* 
FROM cable c
  LEFT JOIN physicalpoint pdh ON (pdh.id = c.cab_downhill)
  LEFT JOIN physicalpoint puh ON (puh.id = c.cab_uphill)
  LEFT JOIN interconnect idh ON (idh.id = pdh.id)
  LEFT JOIN interconnect iuh ON (iuh.id = puh.id)
WHERE idh.id='XXXX' OR iuh.id='XXXX'

我希望这很全面......提前谢谢。

编辑：我写的sql查询是这样的：

Sensor

Answer 1

您使用与编写SQL查询完全相同的方式编写它：

PATH=/usr/local/bin:/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/sbin:/opt/aws/bin:/home/ec2-user/bin
SHELL=/bin/bash

* * * * * /opt/monitor/monitor.sh >> /var/log/monitor.log 2>&1
0 3 * * * /opt/monitor/monitor-log-clean.sh >> /var/log/monitor.log 2>&1

sqlalchemy核心中的关联表

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