提取SimpleXMLElement PHP

Question

我有这个XML文件：

http://api.radionomy.com/currentsong.cfm?radiouid=80b5e81c-c769-478a-aee7-fbe149aacfe3&apikey=cf415862-c0ac-4085-bc03-be80a26f9063&callmeback=yes&type=xml&cover=yes&previous=yes.xml

我想打印内容xml标签

我试过了：

<?php

$xml = 'http://api.radionomy.com/currentsong.cfm?radiouid=80b5e81c-c769-478a-aee7-fbe149aacfe3&apikey=cf415862-c0ac-4085-bc03-be80a26f9063&callmeback=yes&type=xml&cover=yes&previous=yes.xml';
$xmlcont = new SimpleXMLElement($xml);

echo $xmlcont->track->title;

?>

但它不起作用!!

Answer 1

使用以下内容：

$xmlObj = new SimpleXMLElement('http://api.radionomy.com/currentsong.cfm?radiouid=80b5e81c-c769-478a-aee7-fbe149aacfe3&apikey=cf415862-c0ac-4085-bc03-be80a26f9063&callmeback=yes&type=xml&cover=yes&previous=yes.xml', NULL, TRUE);
$tracks = $xmlObj->xpath("//tracks");
if(count($tracks) > 0) {
    foreach($tracks as $track) {
        echo $track->track->title . "\n";
    }
}

当您需要从网址获取数据时，只需将SimpleXMLElement的第3个参数设置为true