Question

如果我的代码看起来像下面那样，并且喜欢将show类添加到父级和祖级中。

// The last `nav-item` have `active` classs
<div class="nested-group nested-item show">
  <div class="nested-item show">
    <div class="nested-item show">
      <div class="nested-item show">
        <a class="nav-item active" href="#">Lorem</a>
        <a class="nav-item" href="#">Ipsum</a>
      </div>
    </div>
  </div>
</div>

// The last `nav-item` doesn't have `active` class
<div class="nested-group nested-item">
  <div class="nested-item">
    <div class="nested-item">
      <div class="nested-item">
        <a class="nav-item" href="#">Lorem</a>
        <a class="nav-item" href="#">Ipsum</a>
      </div>
    </div>
  </div>
</div>

Answer 1

您可以使用.parents()方法定位nested-item类的所有父/祖先。

＆＃13;

$('.active.nav-item').parents('.nested-item').addClass('show');

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="nested-group nested-item ">
  <div class="nested-item ">
    <div class="nested-item ">
      <div class="nested-item ">
        <a class="nav-item active" href="#">Lorem</a>
        <a class="nav-item" href="#">Ipsum</a>
      </div>
    </div>
  </div>
</div>

＆＃13;

如果项具有活动类，则将类添加到父级和祖级

1 个答案: