Question

我想使用与上一个分类帐

相同的accountid从表中检索最后一行的余额

|---ledgerid---|--accountid--|--blance--|
|     1        |      1      |    500   |
|     2        |      1      |    800   |

我希望输出为

|---ledgerid---|--accountid--|--blance--|
|     2        |      1      |    800   |

Answer 1

尝试使用分区，如下所示。

select * from(select *
,row_number()over(partition by accountid order by ledgerid desc) r 
from
[yourtable])
where r=1
order by accountid

以上查询适用于SQL Server。

Answer 2

您可以根据accountid和ledgerid的降序给出行号。

<强>查询

select t2.`ledgerid`,
       t2.`accountid`,
       t2.`blance`
from (
   select `ledgerid`,
   `accountid`,
   `blance`, ( 
       case `accountid`
       when @curA
       then @curRow := @curRow + 1 
       else @curRow := 1 and @curA := `accountid` end
     ) as `rn`
     from `your_table_name` t,
     (select @curRow := 0, @curA := '') r
     order by `accountid`, `ledgerid` desc
)t2
where t2.`rn` = 1;

<强> Find demo here

Answer 3

如果您的分类帐ID继续递增1，那么您可以使用以下查询来获取最后一行：------

 SELECT TOP 1 * FROM Table ORDER BY LEDGERID DESC

OR

 SELECT * FROM TABLE ORDER BY LEDGERID DESC LIMIT 1

Answer 4

试试这个： -

select * from table_name where accountid=1 order by legerid desc limit 1

Answer 5

SELECT l1.* FROM ledger l1 LEFT JOIN ledger l2 ON 
(l1.accountid = l2.accountid AND l1.ledgerid < l2.ledgerid) 
 WHERE l2.ledgerid IS NULL

如何使用distinct和group by same列获取最后一行

5 个答案: