美好的一天,我的脚本中有这个数组。这是我的数组
Array
(
[0] => Array
(
[0] => BACK
[1] => PACK
[2] => BBP160800103
[3] =>
[4] => G086-1
[5] => 8#.JPG
)
[2] => Array
(
[0] => BACKPACK
[1] => BBP160500010
[2] => G114-3#1.JPG
)
[3] => Array
(
[0] => WSL160800024-WSL160800025
[1] => L83-5.JPG
)
[4] => Array
(
[0] => IA041017
[1] => L83-5.JPG
)
)
我从这个脚本中获取数组。我使用codeigniter 3
public function generatenewname(){
$this->load->helper('directory');
$map = directory_map( './assets/file_upload/md/temp/',FALSE, TRUE);
for($x=0;$x<count($map);$x++){
$newest[$x] = explode(" ",$map[$x]);
}
echo "<pre>";print_r($newest);
}
所以从上面的数组中我想得到这个值BBP160800103,BBP160500010,WSL160800024,WSL160800025
和IA041017
我该如何实现呢?
- UPDATE -
我从我的脚本做了一些更新(我正在尝试)
public function generatenewname(){
$this->load->helper('directory');
$map = directory_map( './assets/file_upload/md/temp/',FALSE, TRUE);
for($x=0;$x<count($map);$x++){
$newest[$x] = explode(" ",$map[$x]);
for($y=0;$y<count($newest[$x]);$y++){
if(strlen($newest[$x][$y]) >= 7){
$file[] =$newest[$x][$y];
}
}
}
for($x=0;$x<count($file);$x++){
echo $x.' '. $file[$x].'<br>';
}
}
对于我上面的脚本,我在列表中得到了这个
[n] BBP160800103
[n] BBP160500010
[n] WSL160800024-WSL160800025
我想实现它
[n] BBP160800103
[n] BBP160500010
[n] WSL160800024
[n] WSL160800025
答案 0 :(得分:2)
您可以根据启动键匹配模式。
$array = [
['BACK', 'PACK', 'BBP160800103', '', 'G086-1', '8#.JPG'],
['BACKPACK', 'BBP160500010', 'G114-3#1.JPG'],
['WSL160800024-WSL160800025', 'L83-5.JPG'],
['IA041017', 'L83-5.JPG']
];
$patterns = ['(BBP\w+)', '(WSL\w+)', '(IA\w+)'];
$codes = [];
$matcher = '/' . implode($patterns, '|') . '/';
foreach ($array as $arr) {
array_map(function ($value) use ($matcher, &$codes) {
preg_match_all($matcher, $value, $matches);
foreach($matches as $match) {
$codes = array_merge(array_filter($match), $codes);
}
}, $arr);
}
print_r(array_unique($codes));
// output
Array
(
[0] => IA041017
[2] => WSL160800024
[3] => WSL160800025
[6] => BBP160500010
[8] => BBP160800103
)
答案 1 :(得分:1)
将最终数组传递给此函数以获得结果。
arraymakking($file);//your array
function arraymakking($arr){
foreach($arr as $key=>$val){
if(strpos($val,'-') !== false){
$res=explode('-',$val);
unset($arr[$key]);
}
}
$result=array_merge($arr,$res);
return $result;
}
答案 2 :(得分:-1)
试试这个:
echo $array[0][3]; //BBP160800103
echo $array[2][1]; //BBP160500010
等。请参阅编号索引。使用命名索引创建数组会更好。像这样:
$array = array("Array1"=>array("key1"=>"val1","key2"=>"val2"),"Array2"=>(array("2ndKey1"=>"val1", "2ndKey2"=>"val2));