Question

我是来自js的python的新手。

我正在尝试使用json在客户端和服务器之间进行通信，并且我无法理解python（龙卷风）中对象属性的易于jsonifyable等价物。从这个SO答案（https://stackoverflow.com/a/2827726/4808079）获取的对象创建的代码会引发一些错误。

class MainHandler(tornado.web.RequestHandler):
    def post(self):
        #getting and parsing json works as expected
        args = json.loads(self.request.body.decode())

        #can't seem to figure out how to make this jsonify well
        out = []
        for num in range(0,5):
            addMe = type('', (), {})
            addMe.value = num
            addMe.square = num * num
            out.append(addMe)

        self.write(json.dumps(out))

控制台错误：

Traceback (most recent call last):
File "/Library/Python/2.7/site-packages/tornado/web.py", line 1509, in _execute
    result = method(*self.path_args, **self.path_kwargs)
File "test_tornado.py", line 43, in post
    self.write(json.dumps(out))
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/__init__.py", line 243, in dumps
    return _default_encoder.encode(obj)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/encoder.py", line 207, in encode
    chunks = self.iterencode(o, _one_shot=True)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/encoder.py", line 270, in iterencode
    return _iterencode(o, 0)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/encoder.py", line 184, in default
    raise TypeError(repr(o) + " is not JSON serializable")
TypeError: <class '__main__.'> is not JSON serializable

相当于我在上面尝试的内容就像在JavaScript中一样：

var out = []
for(var num = 0; num < 5; num++) {
    var addMe = {};
    addMe.value = num;
    addMe.square = num*num;
    out.push(addMe);
}
return JSON.stringify(out);

我应该如何在Python中构建一个对象以便JSON化好？

Answer 1

您可以直接编码dicts：

addMe = {
    'value': num,
    'square': num * num
}

我如何构建python对象以使它们JSONify好？

1 个答案: