Question

我收到一些数据库日期，他们可能会混淆。我使用sorted（）方法定期打印这些日期

datelist = ["1 2017", "2 2017", "6 2017",  "7 2017", "8 2017", "3 2017", "4 2017", "5 2017", "9 2017", "10 2017", "11 2017", "12 2017"]

for i in sorted(datelist):
        print(i)

但结果很可怕......！

如何定期获取这些值？在此先感谢您的帮助

Answer 1

使用key sorted参数解析字符串并按datetime排序：

from datetime import datetime
datelist = ["1 2017", "2 2017", "6 2017",  "7 2017", "8 2017", "3 2017", "4 2017", "5 2017", "9 2017", "10 2017", "11 2017", "12 2017"]
for i in sorted(datelist,key=lambda s: datetime.strptime(s,'%m %Y')):
    print(i)

输出：

Answer 2

这是因为您正在对字符串值执行排序，并且字符串的排序已完成lexicographically。为了按数字升序对列表中的字符串进行排序，您可以将key参数作为 lambda 函数传递给sorted：

>>> datelist = ["1 2017", "2 2017", "6 2017",  "7 2017", "8 2017", "3 2017", "4 2017", "5 2017", "9 2017", "10 2017", "11 2017", "12 2017"]

>>> sorted(datelist, key=lambda x: [int(y) for y in x.split()])
['1 2017', '2 2017', '3 2017', '4 2017', '5 2017', '6 2017', '7 2017', '8 2017', '9 2017', '10 2017', '11 2017', '12 2017']

python datetime错误排序

2 个答案: