Question

我的Angular应用程序中有以下界面：

interface Reservation {
  id: string;
  from: Date;
  to: Date;
}

interface Bedroom {
  id: string;
  reservations: Array < Reservation > ;
}

interface House {
  id: string;
  bedrooms: Array < Bedroom >;
}

在某些时候，我必须从Reservation Bedroom内的某个Array内删除House并返回整个House的副本1}} Array仅在没有删除Reservation项的情况下。

我无法改变Array的现有House。我该怎么做？

Answer 1

你应该在你的数组上使用splice方法，使用对象克隆的组合（即由underscore.js提供）： https://www.w3schools.com/jsref/jsref_splice.asp http://underscorejs.org/#clone

这将是（我没有检查代码）：

import * as _ from 'underscore';
removeReservation(bedroom: Bedroom, reservation: Reservation): Bedroom {
    let position = bedroom.reservations.findIndex(checkingRes => {
         return checkingRes.id == reservation.id
    });
    let bedroomCopy = _.clone(bedroom);
    bedroomCopy.reservations.splice(position, position + 1);
    return bedroomCopy;
}

如果您想要逐个删除预订，只需省略克隆操作。

removeReservation(bedroom: Bedroom, reservation: Reservation): Bedroom {
    let position = bedroom.reservations.findIndex(checkingRes => {
         return checkingRes.id == reservation.id
    });
    bedroom.reservations.splice(position, position + 1);
    return bedroom;
}

返回没有给定对象的数组

1 个答案: